Javascript - 通话功能2内功能1，然后继续

Question

可能吗？这个怎么做？点击按钮时，我打电话给function1。如果条件为真（i==1），则function1会暂停，并且仅在function2完全执行后才会执行以下代码。例如：

function1(i){ 
    //some code here 
    if(i == 1){ 
     function2(i); // call function2 and waits the return to continue 
    } 
    //the following code 
} 

function2(i){ 
    //do something here and returns 
} 

Answer 1

在这里你去：

function1(i){ 
    //some code here 
    if(i == 1){ 
     function2(i); // call function2 and waits the return to continue 
    } 
    //the following code 
} 

function2(i){ 
    //do something here and returns 
} 

如果你意味着function2实际上是异步以某种方式：

function1(i){ 
    //some code here 
    if(i == 1){ 
     // call function2 and waits for return to continue 
     function2(i, function() { 
      // the following code 
     }); 
    } 
    else { 
     //the following code 
    } 
} 

function2(i, callback){ 
    //do something async here and return when complete 
    setTimeout(callback, 1000); 
}