与分组的复杂的总和

我有表名为游戏与列：Player1Id，Player2Id，Player1Points，Player2Points。与分组的复杂的总和

的样本数据：

Player1Id Player2Id Player1Points Player2Points 
--------- --------- ------------- ------------- 
John   Piter  4     1 
John   Adam   2    10 
Piter  Adam   4     2

而且我想与点的总和列表每个球员，这样的：

PlayerId Points 
-------- ------ 
John   6 
Piter  5 
Adam  12

如何才达到，在SQL（SQL Server 2008中）？如果只有某位球员赢得比赛，我需要总积分？它可以不使用变量，循环等？

来源

2010-06-22 Abc

SELECT Player1Id AS PlayerId, SUM(Player1Points) AS Points FROM 
(SELECT Player1Id, Player1Points FROM MyTable 
UNION ALL 
SELECT Player2Id, Player2Points FROM MyTable) t1 
GROUP BY Player1Id 
ORDER BY Player1Id

产量：

PlayerId  Points 
--------  ------ 
Adam    12 
John    6 
Piter    5

如果你添加更多的玩家查询将获得更加复杂。最好在不同的行上记录每个玩家的分数。你可以添加一列来指定游戏。

PlayerId Points GameId 
-------- ------ ------ 
John   4  1 
Piter   1  1 
John   2  2 
Adam   10  2 
Piter   4  3 
Adam   2  3

您的查询将被简单：

SELECT PlayerId, SUM(Points) 
FROM MyTable 
GROUP BY PlayerId 
ORDER BY PlayerId

来源

2010-06-22 14:28:14

这应该是'UNION ALL'（如果约翰在两场比赛中得分3，它只会计算一次） – Quassnoi 2010-06-22 14:31:19

@Quassnoi，修正了，谢谢！ – 2010-06-22 14:33:27

我会忍不住重新组织数据，也许是：

Gameid Player Score 
    1 John  4 
    2 John  2 
    1 Piter 1

等

来源

2010-06-22 14:30:17 Patrick

另外，如果您开始与3名玩家进行游戏，则不必添加列。 + 1用于建议标准化数据。 – HLGEM 2010-06-22 14:42:09

测试表：

DECLARE @Table TABLE (Player1Id VARCHAR(17), Player2Id VARCHAR(17), Player1Points INT, Player2Points INT); 
INSERT INTO @Table 
    SELECT 'John', 'Piter', 4, 1 UNION ALL 
    SELECT 'John', 'Adam', 2, 10 UNION ALL 
    SELECT 'Piter', 'Adam', 4, 2;

个

总积分：从赢得比赛

WITH CTE (PlayerId, Points) AS (
    SELECT Player1Id, Player1Points FROM @Table 
    UNION ALL 
    SELECT Player2Id, Player2Points FROM @Table 
) 
SELECT PlayerId, SUM(Points) FROM CTE GROUP BY PlayerId;

总积分：

WITH CTE (PlayerId, Points, Won) AS (
    SELECT Player1Id, Player1Points, CASE WHEN Player1Points > Player2Points THEN 1 ELSE 0 END FROM @Table 
    UNION ALL 
    SELECT Player2Id, Player2Points, CASE WHEN Player2Points > Player1Points THEN 1 ELSE 0 END FROM @Table 
) 
SELECT PlayerId, SUM(Points) FROM CTE WHERE Won = 1 GROUP BY PlayerId;

差异：

WITH CTE (PlayerId, Points) AS (
    SELECT Player1Id, CASE WHEN Player1Points > Player2Points THEN Player1Points - Player2Points ELSE (Player2Points - Player1Points) * -1 END FROM @Table 
    UNION ALL 
    SELECT Player2Id, CASE WHEN Player2Points > Player1Points THEN Player2Points - Player1Points ELSE (Player1Points - Player2Points) * -1 END FROM @Table 
) 
SELECT PlayerId, SUM(Points) FROM CTE GROUP BY PlayerId;

来源

2010-06-22 14:32:53 Don

这只会计算分数的胜利：

SELECT player, SUM(score) AS score 
FROM (
     SELECT player1id AS player, player1points AS score 
     FROM mytable 
     WHERE player1points > player2points 
     UNION ALL 
     SELECT player2id, player2points 
     FROM mytable 
     WHERE player2points > player1points 
     ) q 
GROUP BY 
     player

来源

2010-06-22 14:33:23 Quassnoi

要回答你的第二个问题，然后你可以改变马库斯的答案是：

SELECT 
    Player1Id, 
    SUM(Player1Points) 
FROM 
(
    SELECT Player1Id, Player1Points FROM MyTable WHERE Player1Points >= Player2Points 
    UNION ALL 
    SELECT Player2Id, Player2Points FROM MyTable WHERE Player2Points >= Player1Points 
) t1 
GROUP BY 
    Player1Id

根据您想如何处理的关系，你需要改变> =。

来源

2010-06-22 14:35:58

与分组的复杂的总和

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