使用相同的密钥和值到一个单一的词典合并字典

Question

我有一个列表的字典中它看起来像这样：

{"items":[{"number":"98", "items": {"code": "X", "color": "Red"}},{"number":"98", "items": {"code": "Y", "color": "Blue"}},{"number":"62", "items": {"code": "B", "color": "Green"}}{"number":"62", "items": {"code": "A", "color": "Yellow"}}]} 

有没有一种方法，我可以合并的每个“数字”的项目这些值是否一致成为一个像这样的列表？

{"items":[{"number":"98","items":[{"code":"X","color":"Red"}, {"code": "Y","color":"Blue"}]}, {"number":"62", "items": [{"code": "B", "color": "Green"},{"code": "A", "color":"Yellow"}]}]} 

Answer 1

我能想到的最简单的方法就是将所有'项目'分类到中间字典中，按'数字'分组。从那里，将字典转换为所需的输出是微不足道的。

inp = {"items":[{"number":"98", "items": {"code": "X", "color": "Red"}},{"number":"98", "items": {"code": "Y", "color": "Blue"}},{"number":"62", "items": {"code": "B", "color": "Green"}},{"number":"62", "items": {"code": "A", "color": "Yellow"}}]} 
d = dict() 
for i in inp['items']: 
    d[i['number']] = d.get(i['number'], list()) + [i['items']] 
out = {'items': [{'number': n, 'items': d[n]} for n in d.keys()]} 

输出：

{'items': [{'number': '98', 'items': [{'code': 'X', 'color': 'Red'}, {'code': 'Y', 'color': 'Blue'}]}, {'number': '62', 'items': [{'code': 'B', 'color': 'Green'}, {'code': 'A', 'color': 'Yellow'}]}]}