字符串包含如果我有以下特定字符

Question

：

name="paula" 

list=["l", "p"] 

for x in list: 
    print name.count(x) 

>>> 
1 
1 

其中，如果我理解正确的，走的是字符串："paula"并确认它有一个"l"和一个"p"字符。

但如果我想这样做的：

#**if name has both Letters, l and p, then it is a mouse** 

name="paula" 

list_1=["l"] 
list_2=["p"] 
list_3=["l", "p"] 

for y in list_3: 
    if name.count(y): 

    print "%s contains the letters %s and %s. %s is a mouse." % (name,w,x,name) 

#assume w and x are already defined 


>>> 

paula contains the letters l and p. paula is a mouse. 
paula contains the letters l and p. paula is a mouse. 

显然，这是行不通的。我意识到在这段代码中，它将检查字符串"paula"的字母"l"。然后它再次运行以查看它是否包含"p"。因此两个输出而不是一个。

我相信for循环可能需要被丢弃。

任何帮助表示赞赏的家伙！

@两位Alchemist-原因3列出：

#cat, dog, mouse 
#if name contains the letter "L", then it is a cat 
#if name contains the Letter "P", then it is a dog 
#if Name has both Letters, L and P, then it is a mouse 
#if Name has no L or P, then loop the question 


name="lily" 
name_2="patrick" 
name_3="paula" 

list_1=["l"] 
list_2=["p"] 
list_3=["l", "p"] 


for w in list_1: 
    if name.count(w): 
     print "%s contains the letter %s. %s is a cat." %(name,w,name) 

for x in list_2: 
    if name_2.count(x): 
     print "%s contains the letter %s. %s is a dog." %(name_2,x,name_2) 

for y in list_3: 
    if name_3.count(y): 
     print "%s contains the letters %s and %s. %s is a mouse." %(name_3,w,x,name_3) 

Answer 1

我认为最好的方法是使用套。

name = 'paula' 
seek = 'pl' 

if set(seek).issubset(set(name)): 
    print "{0} contains the letters '{1}'. {0} is a mouse.".format(name, seek) 

>>> paula contains the letters 'pl'. paula is a mouse. 

Answer 2

如果我理解正确，你想检查一个字符串列表是否可以在另一个字符串中找到？

如果是这样，你可以做这样的事情：

list3 = ["l", "p"] 
name = "paula" 
if all(char in name for char in list3): 
    print "{0} is a mouse.".format(name) 

从本质上讲，如何代码工作是，它使用一台发电机与“所有”操作相结合。

代码段char in name for char in list3将遍历list3中的每个项目，并且将报告真或假值，而不管该字符是否存在于名称内。这种语法称为生成器理解，与列表解析非常相似，您可以了解更多关于here的信息。

简而言之，char in name for char in list3是做类似下面的内容：

temp = [] 
for char in list3: 
    temp.append(char in name) 
print temp 

>>> [True, True] 

接下来，all功能是内置的是需要的bool的列表，并返回True只有当列表中的每个元素也是True。

综合考虑，只有当列表中的每个字符都可以在name的内部找到时，表达式all(char in name for char in list3)才会评估为True。

Answer 3

使用any()检查字符串中存在列表的内容：

name = "paula" 
list_1 = ["l", "p"] 
if any(word in name for word in list_1): 
    print 'paula is a mouse'