如何从此列表元组中返回一个随机密钥值?我只关心返回'r','p'或's'的动作。从列表元组返回随机值
# Snippet
moves = [('r', "rock"), ('p', "paper"), ('s', "scissors")]
view_all(moves):
print "Player moves:"
for move in moves:
print " => ".join((move[0], move[1]))
如何从此列表元组中返回一个随机密钥值?我只关心返回'r','p'或's'的动作。从列表元组返回随机值
# Snippet
moves = [('r', "rock"), ('p', "paper"), ('s', "scissors")]
view_all(moves):
print "Player moves:"
for move in moves:
print " => ".join((move[0], move[1]))
>>> import random
>>> moves = [('r', "rock"), ('p', "paper"), ('s', "scissors")]
>>> random.choice(moves)
('s', 'scissors')
如果只有元组的第一个值被通缉:
random.choice(moves)[0]
>>> import random
>>> moves = [('r', "rock"), ('p', "paper"), ('s', "scissors")]
>>> print random.choice(moves)[0]
's'
import random
moves = [('r', "rock"), ('p', "paper"), ('s', "scissors")]
move_keys = [ x[0] for x in moves ]
print random.choice(move_keys)
使用random模块。
random.choice(A)
或A[random.randint(0,len(A)-1)]
感谢您的文档的链接,我不太确定如何使用选择。为我节省了很少的头痛! – theGrayFox
很高兴看到它有一些帮助。 ;) – zhangyangyu