Laravel Dingo API - 如何应对多个收藏品/变形金刚？

Question

要初始化我的应用程序，我有以下途径：

/initialize

这将返回分类法，枚举接口和像收藏其他几个分类的。这节省了多个HTTP请求。

虽然与Dingo/Fractal，我不明白我如何能与多个集合作出回应？

例如

return [ 
    'taxonomies' => $this->response->collection($taxonomies, new TaxonomyTransformer); 
    'enumerables' => $this->response->collection($enumerables, new EnumerableTransformer); 
    'otherStuff' => $this->response->collection($otherStuff, new OtherStuffTransformer); 
]; 

Answer 1

return response()->json([ 
    'data' => [ 
     'taxonomies' => $this->fractal->collection($taxonomies, new TaxonomyTransformer); 
     'enumerables' => $this->fractal->collection($enumerables, new EnumerableTransformer); 
     'otherStuff' => $this->fractal->collection($otherStuff, new OtherStuffTransformer); 
    ] 
], 200); 

这应该在你正在寻找的格式返回JSON。

Answer 2

我有同样的问题，我从How to use Transformer in one to many relationship. #1054找到解决方案。 这里是我想要返回与我的控制器中的流浪者的流浪者的集合。

$user = User::where('email','=',$input['email'])->with('departments')->with('roles')->get(); 

DepartmentTransformer

class DepartmentTransformer extends TransformerAbstract 
{ 
    public function transform($department) 
    { 
     return [ 
      'id' => $department['id'], 
      'name' => $department['name'], 
      'level' => $department['level'], 
      'parent_id' => $department['parent_id'] 
     ]; 
    } 
} 

RolesTransformer

class RolesTransformer extends TransformerAbstract 
{ 
    public function transform($role) 
    { 
     return [ 
      'name' => $role['name'], 
      'slug' => $role['slug'], 
      'description' => $role['description'], 
      'level' => $role['level'] 
     ]; 
    } 

} 

UserTransformer

class UserTransformer extends TransformerAbstract 
{ 
    protected $defaultIncludes = ['departments','roles']; 


    public function transform($user) 
    { 
     return [ 
      'id' => $user['id'], 
      'name' => $user['name'], 
      'email' => $user['email'], 
      'phone' => $user['phone'], 
     ]; 
    } 


    public function includeDepartments(User $user) 
    { 
     $dept = $user->departments; 

     return $this->collection($dept, new DepartmentTransformer()); 
    } 


    public function includeRoles(User $user) 
    { 
     $rl = $user->roles; 

     return $this->collection($rl, new RolesTransformer()); 
    } 
} 

在我的控制器

$user = User::where('email','=',$input['email'])->with('departments')->with('roles')->get(); 

return $this->response->collection($user, new UserTransformer()); 

而且我得到的结果

  "data": { 
      { 
       "id": 43, 
       "name": "test7", 
       "email": "test7@foxmail.com", 
       "phone": "186********", 
       "departments": { 
       "data": { 
        { 
         "id": 1, 
        "name": "业务一部", 
        "level": 1, 
        "parent_id": 0 
        } 
       } 
       }, 
       "roles": { 
       "data": { 
        { 
         "name": "agent", 
        "slug": "agent", 
        "description": "业务员", 
        "level": 1 
        } 
       } 
       } 
      } 
      } 

请留意$ defaultIncludes并在UserTransformer.You includeXXX（）methonds的使用可以从Fractal Doc获得更详细的信息的。