我试图从Facebook页面上拉墙贴,但我遇到了问题。我没有解析JSON的Twitter feed,所以我看不到我遇到了什么问题。解析PHP中的Facebook JSON时遇到问题
这里是我的代码,并here's the tutorial I used for help:
<?php
$url = "http://www.facebook.com/feeds/page.php?format=json&id=96551536516";
function disguise_curl($url) {
$curl = curl_init();
$header[0] = "Accept: text/xml,application/xml,application/xhtml+xml,";
$header[0] .= "text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5";
$header[] = "Cache-Control: max-age=0";
$header[] = "Connection: keep-alive";
$header[] = "Keep-Alive: 300";
$header[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7";
$header[] = "Accept-Language: en-us,en;q=0.5";
$header[] = "Pragma: ";
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_USERAGENT, 'Mozilla');
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_REFERER, '');
curl_setopt($curl, CURLOPT_ENCODING, 'gzip,deflate');
curl_setopt($curl, CURLOPT_AUTOREFERER, true);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_TIMEOUT, 10);
$html = curl_exec($curl);
curl_close($curl);
return $html;
}
$response = json_decode(disguise_curl($url));
foreach($response->entries as $block){
echo
"<li class='clearfix'>
<div class='streamPosterName'>{$block->author}</div>
<div class='postContent'>{$block->title}</div>
</li>";
}
?>
当我的网页的其他部分解析JSON,我使用引用JSON对象下面的方法:
<?php
$url = "http://search.twitter.com/search.json?q=Apple&rpp=50";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$curlout = curl_exec($ch);
curl_close($ch);
$response = json_decode($curlout, true);
foreach($response["results"] as $block){
echo
"<li class='clearfix'>
<img src='".$block["profile_image_url"]."' />
<div class='streamPosterName'>".$block["from_user_name"]."</div>
<div class='streamPosterUsername'>@".$block["from_user"]."</div>
<div class='postContent'>".$block["text"]."</div>
</li>";
}
?>
上面的代码正确拉入推文。 Facebook的解析提供下列错误:
Catchable fatal error: Object of class stdClass could not be converted to string in /home/public_html/mkt/index.php on line 260
260线如上所示:
<div class='streamPosterName'>{$block->author}</div>
如果您定义'不工作' – scoota269
Woops,将会有帮助。 – Jon
这只是意味着$ block-> author是Object类型而不是String,因此不会回显 – Stefan