组成的命令，在bash

Question

超时参数，我可以使用超时为：

timeout 5s sleep 6s 

但我怎么能传递给更多的超时复杂的命令？我试过以下，但所有给我的错误：几乎立即

timeout 5s sleep 6s && echo "You did not fit in timeout" 
timeout 5s 'sleep 6s && echo "You did not fit in timeout"' 
timeout 5s {sleep 6s && echo "You did not fit in timeout"} 
timeout 5s (sleep 6s && echo "You did not fit in timeout") 

Answer 1

看一看这样的：

$ timeout 5 sleep 2 && echo OK || echo "You did not fit in timeout" 
OK 
$ timeout 1 sleep 2 && echo OK || echo "You did not fit in timeout" 
You did not fit in timeout 

Answer 2

张贴后，我想通了：

timeout 5s sh -c 'sleep 6s && echo "You did not fit in timeout"' 

有没有更好的解决办法？