2016-12-01 50 views
0

我有以下代码我必须从服务器获取响应代码吗?

URL url = new URL(pushURL); 
HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
conn.setDoOutput(true); 
conn.setRequestMethod("POST"); 
conn.setRequestProperty("Content-Type", "application/restService"); 
conn.setConnectTimeout(30000); 
conn.setReadTimeout(30000); 
if(conn.getResponseCode() == 200){ 
    logger.debug("Success"); 
} else {     
    logger.debug("Time out set for 30 seconds"); 
} 
String input = writer.getBuffer().toString(); 
OutputStream os = conn.getOutputStream(); 

如果我不感兴趣,从服务器的响应,我可以去掉下面的代码?

if(conn.getResponseCode() == 200){ 
    logger.debug("Success"); 
} else {     
    logger.debug("Time out set for 30 seconds"); 
} 

考虑到该代码,在它的全部,因为它是导致java.net.ProtocolException,是有办法还是抢服务器响应并执行conn.getOutputStream();?按什么顺序?除了明显的报告问题之外,没有获得回应的后果是什么?

回答

2

问题是,一旦你得到响应码,你就发送了你的帖子。在您的代码中,在获得响应之前,您不会向输出流写入任何内容。所以,你基本上什么都不发送(只是这个头文件信息),得到响应代码,然后再次尝试写入,这是不允许的。你需要做的是写入到输出流,然后再获得响应代码如下所示:

public static void main(String[] args) throws IOException { 
    URL url = new URL(pushURL); 
    HttpURLConnection conn = (HttpURLConnection) url.openConnection(); 
    conn.setDoOutput(true); 
    conn.setRequestMethod("POST"); 
    conn.setRequestProperty("Content-Type", "application/restService"); 
    conn.setConnectTimeout(30000); 
    conn.setReadTimeout(30000); 
    String input = writer.getBuffer().toString(); 
    OutputStream os = conn.getOutputStream(); 
    for (char c : input.toCharArray()) { 
     os.write(c); 
    } 
    os.close(); 

    if(conn.getResponseCode() == 200){ 
     System.out.println("Success"); 
    } else {     
     System.out.println("Time out set for 30 seconds"); 
    } 
} 

这里有一个小教程:

Reading and Writing Tutorial

+0

谢谢你的回答和教程 – Mushy