我有个问题,我找不出来。我写了这个代码洗牌数组的元素:使用const替代变量声明的空指针
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
const char *array[]={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
int main(int argc, char **argv)
{
int i, tmp, randomize, size;
size = sizeof(array)/sizeof(*array);
srand(time(NULL));
for(i=size;i>0;i--){
randomize=0+(rand()%size);
tmp=(int)array[i];
array[i]=array[randomize];
array[randomize]=(char*)tmp;
}
for(i=0;i<size;i++)
printf("%s", array[i]);
return 0;
}
当我运行程序,这是iutput:
azlngiwexbv(null)uscphqjyrodmtk
我不明白为什么指针有时是零,我不明白为什么,以这种方式更改源代码:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main(int argc, char **argv)
{
char *array[]={"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
int i, tmp, randomize, size;
size = sizeof(array)/sizeof(*array);
srand(time(NULL));
for(i=size;i>0;i--){
randomize=0+(rand()%size);
tmp=(int)array[i];
array[i]=array[randomize];
array[randomize]=(char*)tmp;
}
for(i=0;i<size;i++)
printf("%s", array[i]);
return 0;
}
一切工作正常。 谢谢。
'tmp =(int)array [i];'...为什么? –
要避免此警告: –
警告:赋值使指针中的整数不会投射[-Wint-conversion] tmp = array [i]; ^ –