PHP - 字符串逻辑解析 - “X AND Y OR Z”

Question

我想利用一个和/或未知长度的逻辑查询查询字符串：

$logic = 'elephants and tigers or dolphins and apes or monkeys and humans and gorillas and and 133322 or 2'; 

它解析成一个数组，我假定将看起来是这样的：

$parsed_to_or = array(
    array('elephants', 'tigers'), 
    array('dolphins', 'apes'), 
    array('monkeys', 'humans', 'gorillas', '133322'), 
    array('2') 
); 

这是我到目前为止有：

$logic_e = preg_split('/\s+/', $logic); 
$or_segments = array(); 
$and_group = array(); 
foreach($logic_e as $fragment) { 
    if (preg_match('/^(and|&&)$/i', $fragment)) { 
    continue; 
    } elseif (preg_match('/^(or|\\|\\|)$/i', $fragment)) { 
    if (count($and_group)>0) { 
    $or_segments[] = $and_group; 
    $and_group = array(); 
    } continue; 
    } else { 
    $and_group[] = $fragment; 
    continue; 
    } 
} 
if (count($and_group)>0) { 
    $or_segments[] = $and_group; 
    $and_group = array(); 
} 

任何更好的办法来解决呢？

Answer 1

更新：增加了使用& &和||的能力。随时随地

你可以做到以下几点：

<?php 

$logic = 'elephants && tigers || dolphins && apes || monkeys and humans and gorillas and && 133322 or 2'; 

$result = array(); 
foreach (preg_split('/ (or|\|\|) /', $logic) as $parts) { 
    $bits = preg_split('/ (and|&&) /', $parts); 
    for ($x=0; $x<count($bits); $x++) { 
    $bits[$x] = preg_replace('/\s?(and|&&)\s?/', '', $bits[$x]); 
    } 
    $result[] = $bits; 
} 

echo '<pre>'; 
var_dump($result); 

这将导致以下：

array(4) { 
    [0]=> 
    array(2) { 
    [0]=> 
    string(9) "elephants" 
    [1]=> 
    string(6) "tigers" 
    } 
    [1]=> 
    array(2) { 
    [0]=> 
    string(8) "dolphins" 
    [1]=> 
    string(4) "apes" 
    } 
    [2]=> 
    array(4) { 
    [0]=> 
    string(7) "monkeys" 
    [1]=> 
    string(6) "humans" 
    [2]=> 
    string(8) "gorillas" 
    [3]=> 
    string(6) "133322" 
    } 
    [3]=> 
    array(1) { 
    [0]=> 
    string(1) "2" 
    } 
} 

Answer 2

如何：

$logic = 'elephants and tigers or dolphins and apes or monkeys and humans and gorillas and and 133322 or 2'; 
$ors = preg_split('/(\bor\b|\s\|\|\s)/', $logic); 

foreach ($ors as &$or) { 
    $or = array_filter(array_map('trim', preg_split('/(\band\b|\s&&\s)/', $or))); 
} 

var_dump($ors); 

Answer 3

使用explode是更简单：

$logic = 'elephants and tigers or dolphins and apes or monkeys and humans and gorillas and and 133322 or 2'; 

    $parts = explode(" or ", $logic); 

    foreach($parts as $part){ 
     if(!empty($part)){ 
      $finalArray[] = explode(" and ", $part); 

     } 
    } 

    print_r($finalArray); 

，将返回：

Array 
(
    [0] => Array 
     (
      [0] => elephants 
      [1] => tigers 
     ) 

    [1] => Array 
     (
      [0] => dolphins 
      [1] => apes 
     ) 

    [2] => Array 
     (
      [0] => monkeys 
      [1] => humans 
      [2] => gorillas 
      [3] => and 133322 
     ) 

    [3] => Array 
     (
      [0] => 2 
     ) 

) 

Answer 4

这将处理gorillas问题，而空条目，如and and

$logic = 'elephants and tigers or dolphins and apes || monkeys and humans and gorillas and and 133322 or 2'; 

$arrayBlocks = preg_split('/(\bor\b|\|\|)/', $logic); 
array_walk(
    $arrayBlocks, 
    function(&$entry, $key) { 
     $entry = preg_split('/(\band\b|&&)/', $entry); 
     $entry = array_filter(
      array_map(
       'trim', 
       $entry 
      ) 
     ); 
    } 
); 

var_dump($arrayBlocks); 

虽然array_filter也将清洁0进入

Answer 5

什么我想我会去：

$or_segments = array(); 
foreach(preg_split('/((\\s+or\\s+|\\s*\\|\\|\\s*))+/i', $logic) as $or_split_f) {   
$or_segments[] = preg_split('/((\\s+and\\s+|\\s*&&\\s*))+/i', $or_split_f); 
} 
var_dump($or_segments);