满足条件时回路无法终止

Question

为什么满足所需条件时回路无法终止？ 我将不胜感激深入的解释，而不是为我纠正的代码。

def get_name(name_type): 
    return raw_input("Please enter you're {}name: \n".format(name_type)) 
def UserName(): 
    result = get_name("Fore"), get_name("Middle"), get_name("Sur") 
    return " ".join(result) 

print("You're UserName is : " + UserName()) 

while True: 
    def Base(): 
     return int(raw_input("Please select a base number: \n")) 
    def Power(): 
     return int(raw_input("Please select a power number: \n")) 
    def result(): 
     return Base()*Power() 

    print result() 

    cont = raw_input("Would you like to quit? yes/no > ") 
    while cont.lower() not in ("yes","no"): 
      cont = raw_input("Would you like to quit? yes/no > ") 
      if cont=="no": 
       break 

Answer 1

现在它的作用：

def get_name(name_type): 
    return raw_input("Please enter you're {}name: \n".format(name_type)) 
def UserName(): 
    result = get_name("Fore"), get_name("Middle"), get_name("Sur") 
    return " ".join(result) 

print("You're UserName is : " + UserName()) 
print 

cont = 'no' 

while cont != 'yes': 
    def Base(): 
     return int(raw_input("Please select a base number: \n")) 
    def Power(): 
     return int(raw_input("Please select a power number: \n")) 
    def result(): 
     return Base()*Power() 

    print result() 

    cont = raw_input("Would you like to quit? yes/no > ") 
    while cont.lower() not in ("yes","no"): 
      cont = raw_input("Would you like to quit? yes/no > ") 
      if cont=="yes": 
       break 

Answer 2

你内部的两个while循环。 你想摆脱这两个如果用户想要退出，否则只能从内之一：搬出while循环的条件，那么它应该工作：

from sys import exit 

... 

while True: 
    def Base(): 
     return int(raw_input("Please select a base number: \n")) 
    def Power(): 
     return int(raw_input("Please select a power number: \n")) 
    def result(): 
     return Base()*Power() 

    print result() 

    cont = raw_input("Would you like to quit? yes/no > ") 
    while cont.lower() not in ("yes","no"): 
     cont = raw_input("Would you like to quit? yes/no > ") 
    if cont=="yes": 
     break 

下一个忠告与你的问题没有任何关系，但无论如何我会给它：在每个循环迭代中，没有必要定义Base，Power和Result函数。只需将值赋给变量，并直接打印：

base = int(raw_input("Please select a base number: \n")) 
power = int(raw_input("Please select a power number: \n")) 
print base*power 

Answer 3

你break语句嵌套在内while循环内，因此它被打破这个循环，而不是while True循环。我觉得移动的条件语句进行内部循环和改变逻辑if discont=='yes'（注：重命名的变种，以更准确的描述）会给你想要的东西：

while True: 

    ... 

    discont = raw_input("Would you like to quit? yes/no > ").lower() 
    while discont not in ("yes","no"): 
     discont = raw_input("Would you like to quit? yes/no > ").lower() 
    if discont=="yes": 
     break