0
我写了一段代码。C++代码不按预期返回向量,并在转换时抛出错误
它做什么?它打印某些内容,然后要求用户插入他最喜欢的作者的名称,然后将插入的作者添加到矢量中。
在代码的最后两行,分别,作者的矢量分配给一个矢量可变,但在这条线,它会引发下面的代码:
error C2664: 'std::basic_string<char,std::char_traits<char>,std::allocator<char>>::basic_string(std::initializer_list<_Elem>,const std::allocator<char> &)' : cannot convert argument 1 from 'std::vector<std::string,std::allocator<_Ty>>' to 'const std::basic_string<char,std::char_traits<char>,std::allocator<char>> &'
因此,它未达到到最后一行。
但是,我的问题是,我想返回一个由用户添加作者的作者矢量。这会导致问题,因为在此之前,代码正在工作。
下面是代码:
#include "stdafx.h"
#include <iostream>
#include <string>
#include <ctime>
#include <vector>
using namespace std;
class SimpleClass
{
public: string AuthorName;
public: string AuthorLastWork;
vector<string> AuthorNames;
public: int AuthorBirthYear;
private: string AuthorBestSelling;
private: int AuthorNumOfSoldWorks;
public:
void SetAuthorName(string Name)
{
this->AuthorName = Name;
string namesOfAuthors[2] {"Jack London", "Flaubert"};
if (Name == namesOfAuthors[0])
{
this->setAuthorSoldWorks(2000000);
}
else if (Name == namesOfAuthors[1])
{
this->setAuthorSoldWorks(5000);
}
}
int GetAuthorNumOfSoldWorks()
{
return this->AuthorNumOfSoldWorks;
}
private :
void setAuthorSoldWorks(int number)
{
this->AuthorNumOfSoldWorks = number;
}
}; // END OF CLASS
class SecondClass : public SimpleClass
{
public:
void AddAuthor(string name)
{
this->AuthorNames.push_back(name);
}
GetAuthors(string name)
{
return this->AuthorNames;
}
};
int main()
{
string AuthorNameByUser;
SimpleClass SC;
SecondClass SecondClass;
SC.SetAuthorName("Jack London");
cout << "This is our selected Author: " << SC.AuthorName << endl;
cout << "Number of sold works: " << SC.GetAuthorNumOfSoldWorks() << " works." << endl;
cout << endl;
cout << "Please type the name of your favorite author: ";
getline(cin, AuthorNameByUser);
SecondClass.AddAuthor(AuthorNameByUser);
vector<string> AuthorsCollection = SecondClass.GetAuthors();
cout << "Thank for your particpiation. You have entered \"" << AuthorsCollection[0] << "\"" << endl;
}
您错过了'GetAuthors'成员函数的返回值。 – 101010