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有没有办法请求URL并以字符串形式获取响应?Julia - 从网址获取HTML
我试图同时使用“请”包和“libcurl的”,但我不能找到一个方法来做到这一点
Fx的。如果我用我的请求收到错误看起来像
get(url)
ERROR: MbedTLS error code -30592: SSL - A fatal alert message was received from our peer
in macro expansion at /home/david/.julia/v0.5/MbedTLS/src/error.jl:4 [inlined]
in handshake(::MbedTLS.SSLContext) at /home/david/.julia/v0.5/MbedTLS/src/ ssl.jl:145
in open_stream(::HttpCommon.Request, ::MbedTLS.SSLConfig, ::Float64, ::Nullable{URIParser.URI}, ::Nullable{URIParser.URI}) at /home/david/.julia/ v0.5/Requests/src/streaming.jl:209
in #do_stream_request#23(::Dict{AbstractString,AbstractString}, ::Void, ::Void, ::Void, ::Array{Requests.FileParam,1}, ::Void, ::Dict{Any,Any}, ::Bool, ::Int64, ::Array{HttpCommon.Response,1}, ::MbedTLS.SSLConfig, ::Bool, ::Bool, ::Bool, ::Nullable{URIParser.URI}, ::Nullable{URIParser.URI}, ::Requests.#do_stream_request, ::URIParser.URI, ::String) at /home/david/.julia /v0.5/Requests/src/Requests.jl:361
in do_stream_request(::URIParser.URI, ::String) at /home/david/.julia/v0.5/ Requests/src/Requests.jl:324
in #do_request#22(::Array{Any,1}, ::Function, ::URIParser.URI, ::String) at/ home/david/.julia/v0.5/Requests/src/Requests.jl:291
in #get#29(::Array{Any,1}, ::Function, ::URIParser.URI) at /home/david/.julia/ v0.5/Requests/src/Requests.jl:424
in #get#28(::Array{Any,1}, ::Function, ::String) at /home/david/.julia/v0.5/ Requests/src/Requests.jl:423
in get(::String) at /home/david/.julia/v0.5/Requests/src/Requests.jl:423
你的编辑只是彻底改变了你的问题。您不希望将响应作为字符串来获取......因为您根本没有收到任何响应!如果您想帮助调试该错误,则需要发布更多的上下文。你可以在公开的网站上复制它吗?例如,“https:// example.com”适用于我。 –