获取网址

Question

源代码我有以下代码：

import urllib2 
from itertools import product 

with open('urllist.txt') as urllist: 
    urls=[line.strip() for line in urllist] 

for url in product(urls): 
    usock = urllib2.urlopen(url) 
    data = usock.read() 
    usock.close() 
    sourcecode=open('./sourcecode', 'w+') 
    sourcecode.write(data) 

当我运行它，它给了：

Traceback (most recent call last): 
    File "12.py", line 8, in <module> 
    usock = urllib2.urlopen(url) 
    File "/opt/python2.7.1/lib/python2.7/urllib2.py", line 126, in urlopen 
    return _opener.open(url, data, timeout) 
    File "/opt/python2.7.1/lib/python2.7/urllib2.py", line 383, in open 
    req.timeout = timeout 
AttributeError: 'tuple' object has no attribute 'timeout' 

不知道如何解决它？非常感谢！

Answer 1

itertools.product返回一个元组不是项目本身：

>>> from itertools import product 
>>> lis = ['a','b','c'] 
>>> for p in product(lis): 
...  print p 
...  
('a',) 
('b',) 
('c',) 

使用过的URL的简单循环：

for url in urls: 
    usock = urllib2.urlopen(url)