我PDO新手,我不知道如何捕捉错误的或看到什么错呢看看这段代码:PHP PDO更新查询不工作
呼叫这里的功能:
$this->storage->updateTriplet($cookieValues[0],$newToken.$this->salt, $cookieValues[2].$this->salt, $t, $expire);
问题函数:
public function updateTriplet($credential, $token, $persistentToken,$t, $expire=0) {
$sql = "UPDATE {$this->tableName}
SET cred=?, tok=?, ptok=?, t=?, expires=?
WHERE ptok=?'".$persistentToken."' ";
$query = $this->connection->prepare($sql);
$query->execute(array($credential ,$token, $persistentToken , $t , date("Y-m-d H:i:s", $expire)));
}
而且该功能良好,插入功能使用我:
public function storeTriplet($credential, $token, $persistentToken,$t, $expire=0) {
$sql = "INSERT INTO {$this->tableName}({$this->credentialColumn}, " .
"{$this->tokenColumn}, {$this->persistentTokenColumn}, " .
"{$this->t},{$this->expiresColumn}) VALUES(?, SHA1(?), SHA1(?),?, ?)";
$query = $this->connection->prepare($sql);
$query->execute(array($credential, $token, $persistentToken,$t, date("Y-m-d H:i:s", $expire)));
}
无论如何,我的插入功能工作完美问题是在更新功能的第一个,我的更新功能不工作,任何人知道我的问题在哪里,我做错了什么?以及如何查看更新函数上的MySql PDO错误?
更新:回答和解决:
public function updateTriplet($credential, $token, $persistentToken,$t, $expire=0) {
$sql = "UPDATE {$this->tableName}
SET cred=?, tok=?, ptok=?, t=?, expires=?
WHERE ptok=SHA1('".$persistentToken."');
$query = $this->connection->prepare($sql);
$query->execute(array($credential ,$token, $persistentToken , $t , date("Y-m-d H:i:s", $expire)));
}
非常感谢。
我建议你把'$ persistentToken'作为参数传递给你,就像你对别人做的那样。您将确保它将被正确转义。 –