我一直在一个网站上工作,并最近添加了一些更改,尽管试图评论说所做的更改,我的更新查询不工作 - 我一直在试图找出原因在过去的3个小时无济于事。MySQL更新查询(PDO)莫名其妙地不工作
if (isset($_POST['submit']))
{
if (count($rated)<$_SESSION['id'])
{
$difference = $_SESSION['id'] - count($rated);
$rated = implode(',',$rated);
while ($difference >= 0)
{
$rated .= "0,";
$difference--;
}
$rated = explode(',',$rated);
}
$rated[$_SESSION['id']] = $_POST['rating'];
$ratings = 0;
$ratingsadded = 0;
foreach ($rated as $user => $rating)
{
if ($rating != 0)
{
$query = $db->prepare("SELECT id, active FROM accounts WHERE id = :id");
$query->execute(array('id' => $user));
$useractive = $query->fetch();
if ($useractive['active'] == 1 || $user == 0 || $user == 50)
{
$ratings++;
$ratingsadded += $rating;
}
else
{
$rated[$user] = 0;
}
}
}
$ratingtotal = $ratingsadded/$ratings;
$query = $db->prepare("UPDATE accounts SET rating = :rating, rated = :rated WHERE id = :id");
$query->execute(array('rating' => $ratingtotal, 'rated' => implode(",",$rated), 'id' => $user['id']));
header('Location: ?user=' . $_GET['user']);
}
注:最后的查询是我所指的那个。
备注:我知道在我的代码中有很多低效率。
全码:http://pastebin.com/ybb71U6k
看起来好像这会起作用,我的笔记本电脑刚刚崩溃,所以我现在重新启动它,以便我可以测试。 – qwerty77asdf
我删除了我的评论。我可以看到你在'foreach'循环中使用了'$ user'作为数组索引,所以它不是execute语句的问题。 –
@Rajdeep参考我的答案,非常感谢。 – qwerty77asdf