我的代码在这里。当我试图执行时,我得到一个错误的左值,作为程序第二行赋值的左操作数......任何人都可以帮我吗?C程序执行错误
void main()
{
unsigned char name[10]="ERPDIR",buff[30];
(char *)buff = ASCII2HEX(name,buff);
printf("The HEX Value is %s\n", buff);
}
char *ASCII2HEX(unsigned char *Response,unsigned char *buff)
{
int len,hexlen=0,i=0;
unsigned char BUFF[512]="";
#ifdef PRINT_CONSOLE
printf("\n###### ASCII2HEX:");
#endif
len = strlen((char*)Response);
for(i=0;i<len;i++)
{
sprintf((char*)BUFF+(2*i),"%02X",Response[i]);
#ifdef PRINT_CONSOLE
printf("%02X ",Response[i]);
#endif
}
printf("\n");
BUFF[2*i]='\0';
hexlen=len;
memset(buff,0,sizeof(buff));
AsciiStr2HexByte((const char*)BUFF,len*2,buff,&hexlen);
buff[hexlen]='\0';
return 0;
}
什么代码做的到底是什么,它返回0?并且你正在试图将类型转换为char *类型的'char'数组中? – phoxis 2011-05-27 05:01:47