2017-10-07 48 views
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所以我想做一个函数,可以加密和解密到Base64,然后用一个键XOR它。VB.net Base64 + XOR

这里是我到目前为止的代码:

Imports System.Text 

    Module Module1 

    Private key As String = "37526" 


    Sub Main() 
     Dim test As String = Console.ReadLine 
     test = Decrypt(test) 
     Console.WriteLine(test) 
     Main() 

    End Sub 

    Public Function Decrypt(CipherText As String) As String 

     Dim decoded = Convert.FromBase64String(CipherText) 
     Dim dexored = [xor](decoded, key) 
     Return Encoding.UTF8.GetString(dexored) 

    End Function 

    Private Function [xor](text As Byte(), key As String) As Byte() 
     Dim res As Byte() = New Byte(text.Length - 1) {} 
     For c As Integer = 0 To text.Length - 1 
      res(c) = CByte((text(c)) Xor CUInt(Val(c Mod key.Length))) 
     Next 

     Return res 
    End Function 


    Public Function Encrypt(Plaintext As String) 

     Dim encoded = Encoding.UTF8.GetBytes(Plaintext) 
     Dim xored = [xor](encoded, key) 
     Return Convert.ToBase64String(xored) 

    End Function 

End Module 

因此,这里是我的问题:这个代码工作正常,但我试图解密此字符串“X1hZXVoCBQY =”,该字符串的解密应该是“lolol123 ”。我不知道我的代码是否有错,或者密钥不正确。有人可以检查我的代码或给我正确的密钥吗?我试图暴力破解这个关键,但这个结果对我来说并不合适。如果我尝试解密字符串,我没有得到“lolol123”,我得到“_Y [^^”

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Base64不是加密。 XORing的东西不是加密 - 它最多是模糊的 – Plutonix

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@Plutonix,thnkx为了澄清 – MikeWe

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仍然没有解决;( – MikeWe

回答

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xor函数出错了。试图在一行中做太多的事情可能会使事情变得太复杂而无法立即看到正在发生的事情,所以我开始重写它,因为我会怎么做,并且在我开始查看任何事情之前,快速检查显示它正在工作否则:

Option Infer On 
Option Strict On 
' ... 
Private Function [xor](text As Byte(), key As String) As Byte() 
    Dim res As Byte() = New Byte(text.Length - 1) {} 
    Dim keyBytes = Encoding.UTF8.GetBytes(key) 

    For c = 0 To text.Length - 1 
     res(c) = CByte((text(c)) Xor keyBytes(c Mod keyBytes.Length)) 
    Next 

    Return res 

End Function 
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哇!男人!你是最棒的! – MikeWe