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好吧,我可以为这个最新的问题得到一些明确的答案。这个PHP部分不会返回任何响应,但是,我知道数据在那里。有谁知道为什么这会返回文本“错误”?PHP SQL搜索页面返回错误
<html>
<head>
<title>Search</title>
<style type="text/css">
table {
background-color: #FCF;
}
th {
width: 150px;
text-align: left;
}
</style>
</head>
<body>
<h1>Search</h1>
<form method="post" action="search.php">
<input type="hidden" name="submitted" value="true"/>
<label> Search | Category:
<select name="category">
<option value="fname">FName</option>
<option value="lname">LName</option>
</select>
</label>
<label>Search Criteria: <input type="text" name="criteria"/></label>
<input type="submit"/>
</form>
<?php
if (isset($_POST['submitted'])) {
// connect to DB
include('connect.php');
$category = $_POST['category'];
$criteria = $_POST['criteria'];
$query = "SELECT * FROM people WHERE category = '$category'";
$result = mysqli_query($dbcon, $query) or die ('Error');
echo "<table>";
echo "<thead>";
echo "<tr>";
echo "<th>First Name</th>";
echo "<th>Last Name</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
if (mysqli_num_rows($result)) {
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo "<tr>";
echo "<th>" . $row['fname'] . "</th>";
echo "<th>" . $row['lname'] . "</th>";
echo "</tr>";
}
}
echo "</tbody>";
echo "</table>";
}
?>
</body>
</html>
你能指定错误是什么吗? –
您需要为数据库调用添加一些错误处理:'或die('Error')' – jeroen