我正在与下面的代码的问题:问题与阵列
$ids = '"' . implode('", "', $crumbs) . '"';
$motd = array();
$dober = $db->query("SELECT id, name, msg, datetime FROM tbl_depts td INNER JOIN tbl_motd tm ON td.id = tm.deptid WHERE td.id IN (" . $ids . ")");
while ($row = $dober->fetch_array()) {
$motd[] = $row;
}
一个print_r的揭示这一点:
Array
(
[0] => Array
(
[0] => 1
[id] => 1
[1] => Management
[name] => Management
[2] => New Management Rule!
[msg] => New Management Rule!
[3] =>
[datetime] =>
)
[1] => Array
(
[0] => 2
[id] => 2
[1] => Human Resources
[name] => Human Resources
[2] => DPS
[msg] => DPS
[3] =>
[datetime] =>
)
)
因此,我不能使用此代码生成的东西:
foreach ($motd[] as &$value) {
if ($motd['msg'] != "") {
if ($i == 0) {
?>
<li><a href="#" title="content_<?php echo $value['id']; ?>"
class="tab active"><?php echo $value['name']; ?></a></li>
<?
} elseif ($i == $len - 1) {
?>
<li><a href="#" title="content_<?php echo $value['id']; ?>"
class="tab"><?php echo $value['name']; ?></a></li>
<?php } else { ?>
<li><a href="#" title="content_<?php echo $value['id']; ?>"
class="tab"><?php echo $value['name']; ?></a></li>
<?
}
$i++;
}
}
任何想法,我在做什么错在这里?
编辑:你可能会发现很容易理解,如果你读这第一:Optimize this SQL query
请注意,此代码易受sql注入攻击。 –
就像一个旁注......可能'fetch_assoc()'(http://www.php.net/manual/de/mysqli-result.fetch-assoc.php)更适合您的需求吗? – pinkgothic
我可能会错过某些东西,但是你应该在'foreach'之前放置'$ i = 0;',并且''motd''之后不需要'[]'。 – kapa