以下是查看不同数据类型在内存中存储方式的代码。访问连续内存位置时出现打印错误
#include <stdio.h>
void newline(void)
{
putchar('\n');
}
void showbyte(char *string, int len)
{
int i;
for (i = 0; i < len; i++)
printf("%p\t0x%.2x\n", string+i, *(string+i));
}
int main()
{
int i = 12345;
float f = 1234.5;
double d = 1234.5;
char name[] = "12345";
showbyte((char *)&i, sizeof i);
newline();
showbyte((char *)&f, sizeof f);
newline();
showbyte((char *)&d, sizeof d);
newline();
showbyte((char *)&name, sizeof name);
return 0;
}
输出
0x7fff8a9ab2cc 0x39
0x7fff8a9ab2cd 0x30
0x7fff8a9ab2ce 0x00
0x7fff8a9ab2cf 0x00
0x7fff8a9ab2c8 0x00
0x7fff8a9ab2c9 0x50
0x7fff8a9ab2ca 0xffffff9a
0x7fff8a9ab2cb 0x44
0x7fff8a9ab2c0 0x00
0x7fff8a9ab2c1 0x00
0x7fff8a9ab2c2 0x00
0x7fff8a9ab2c3 0x00
0x7fff8a9ab2c4 0x00
0x7fff8a9ab2c5 0x4a
0x7fff8a9ab2c6 0xffffff93
0x7fff8a9ab2c7 0x40
0x7fff8a9ab2b0 0x31
0x7fff8a9ab2b1 0x32
0x7fff8a9ab2b2 0x33
0x7fff8a9ab2b3 0x34
0x7fff8a9ab2b4 0x35
0x7fff8a9ab2b5 0x00
为float 1234.5
的IEEE-754表示是0x449a5000
,以及用于double 1234.5
是0x40934A0000000000
。当它打印float
和double
变量内容时,它显示一个4-byte
内容。
即, 0x7fff8a9ab2ca 0xffffff9a
和 0x7fff8a9ab2c6 0xffffff93
。
但是每个内存位置只能存储数据的1-byte
,那么为什么会发生?
@EricPostpischil谢谢..我没有找到... – noufal