Valgrind错误 - 字符串拆分C

Question

我有这个程序读取一个字符串并将其分为三部分。第一部分是操作码，第二部分是数据，第三部分是关键。使用

例子：

put this is stackoverflow 

opcode: put 
data: this is 
key: stackoverflow 

代码主营：

int main(int argc, char **argv){ 
      char command[MAX_MSG]; 
      fgets(command, sizeof(command), stdin); 
      command[strcspn (command, "\n")] = '\0'; 
      char *aux_command = strdup(command); 
      char *opcode = strtok(command, " ");   
      int success = 0; 
      char *key ; 
      char *data; 
      if(strcmp(opcode, "put") == 0){ 
      key = getKey(strdup(aux_command), opcode); 
      if(key == NULL){ 
        printf("Invalid number of arguments.\n"); 
        success = -1; 
      } 

      else{ 
        data = getData(aux_command, opcode, key); 

      } 
     } 
     printf("opcode: %s\n",opcode); 
     printf("data: %s\n",data); 
     printf("key: %s\n",key);    
     free(aux_command); 

} 

我的问题是，当我运行我的程序与valgrind它给出了这样的结果：

==2663== by 0x4EBD971: strdup (strdup.c:42) 
... 
==2663== definitely lost: 12 bytes in 1 blocks 
==2663== indirectly lost: 0 bytes in 0 blocks 
==2663==  possibly lost: 0 bytes in 0 blocks 
==2663== still reachable: 0 bytes in 0 blocks 
==2663==   suppressed: 0 bytes in 0 blocks 
==2663== 
==2663== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 2 from 2) 

我不不知道为什么会发生这种情况。谢谢。

Answer 1

你应该strdup()符合

key = getKey(strdup(aux_command), opcode); 

由它分配的内存free()内存分配是没有得到释放，因此Valgrind是显示它作为记忆丧失。

的推荐代码：

... 
     char *command =NULL; //declare variable 
     char *key ; 
     char *data; 
     if(strcmp(opcode, "put") == 0){ 
     command = strdup(aux_command); //use variable to store new memory 
     key = getKey(command, opcode); 
     if(key == NULL){ 
       printf("Invalid number of arguments.\n"); 
       success = -1; 
     } 

     else{ 
       data = getData(aux_command, opcode, key); 

     } 
    } 
    printf("opcode: %s\n",opcode); 
    printf("data: %s\n",data); 
    printf("key: %s\n",key);    
    free(aux_command); 
    free(command); //free it when done