我这里有一个问题..MySQL的组返回所有的行
可以说我有这个表...
waktu | tglTransaksiJual | nominal | ongkir | STATUS | idUser
---------------------------------------------------------------------------------------
2013-02-01 00:00:00 | 2013-01-29 15:00:00 | 10000 | 10000 | APPROVED | 1
0000-00-00 00:00:00 | 2013-02-02 15:00:00 | 20000 | 0 | DONE | 2
0000-00-00 00:00:00 | 2013-02-02 15:00:00 | 10000 | 5000 | DONE | 2
2013-02-03 00:00:00 | 2013-02-01 15:00:00 | 20000 | 0 | APPROVED | 3
,我使用此查询
SELECT DISTINCT(date(IF(waktu = '0000-00-00 00:00:00', tglTransaksiJual, waktu))) AS thedate, SUM(nominal+ongkir) AS total
FROM transaksijual
WHERE IF(waktu = '0000-00-00 00:00:00', tglTransaksiJual, waktu) BETWEEN '2013-02-01' AND '2013-02-05' AND status LIKE 'DONE%' AND idUser LIKE '2%'
GROUP BY thedate
ORDER BY thedate ASC
但结果我已经是
thedate | total
-------------------
2013-02-01 | 30000
而且我想要的是l ike this
thedate | total
------------------
2013-02-01 | 0
2013-02-02 | 35000
2013-02-03 | 0
我该怎么做?那可能吗?? 所以得出的结论是..当没有数据我想要得到0值,并获得该行...
你'WHERE'条件指定'DONE'和'ID用户= 2',但这些不匹配任何其他日期列。这是故意的还是什么? – 2013-02-14 04:37:20
是的......我的问题如何返回带0values行时没有条件匹配 – user2070749 2013-02-14 04:49:05