我有建在我的Android应用程序获取列表对象,这对String.xml:如何从资源文件
<string-array name="alerts_value_set">
<AlertValueSet>
<valueSetOid>2.16.840.1.113883.1.11.20.4</valueSetOid>
<code>106190000</code>
<codeSystem>2.16.840.1.113883.6.96</codeSystem>
<displayName>Allergy</displayName>
<codeSystemName>SNOMED CT</codeSystemName>
</AlertValueSet>
<AlertValueSet>
<valueSetOid>2.16.840.1.113883.1.11.20.4</valueSetOid>
<code>281647001</code>
<codeSystem>2.16.840.1.113883.6.96</codeSystem>
<displayName>Adverse Reaction</displayName>
<codeSystemName>SNOMED CT</codeSystemName>
</AlertValueSet>
<AlertValueSet>
<valueSetOid>2.16.840.1.113883.1.11.20.4</valueSetOid>
<code>282100009</code>
<codeSystem>2.16.840.1.113883.6.96</codeSystem>
<displayName>Adverse reaction to substance</displayName>
<codeSystemName>SNOMED CT</codeSystemName>
</AlertValueSet>
<AlertValueSet>
<valueSetOid>2.16.840.1.113883.1.11.20.4</valueSetOid>
<code>160244002</code>
<codeSystem>2.16.840.1.113883.6.96</codeSystem>
<displayName>No known allergies</displayName>
<codeSystemName>SNOMED CT</codeSystemName>
</AlertValueSet>
</string-array>
现在,有一种方法来通过代码编程获取名单?
我也创建这个类(白衣getter和setter):
public class AlertValueSet {
String valueSetOid;
String code;
String codeSystem;
String displayName;
String codeSystemName;
}
http://www.tutorialspoint.com /android/android_xml_parsers.htm –