如何在逗号分隔的Python中分割单个列表值

Question

added = ['hypr1005.ops.colo.cmp.com,web1234.ads.colo.cmp.com,876543,4'] 

上面的变量是一个列表，它包含单值，用逗号分隔，我只是想用逗号分隔这些值并创建一个名单看起来像

added = ['hypr1005.ops.colo.cmp.com','web1234.ads.colo.cmp.com','876543','4'] 

words = added.split(',') 
Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
AttributeError: 'list' object has no attribute 'split' 

猜测分裂只适用于字符串不在列表上，所以我怎么能做到这一点？

Answer 1

呼叫split方法列表（added[0]）的第一个项目：

>>> added = ['hypr1005.ops.colo.cmp.com,web1234.ads.colo.cmp.com,876543,4'] 
>>> added = added[0].split(',') 
>>> added 
['hypr1005.ops.colo.cmp.com', 'web1234.ads.colo.cmp.com', '876543', '4'] 

Answer 2

为了使用分裂，它应该是一个字符串。

>>> added = "'hypr1005.ops.colo.cmp.com','web1234.ads.colo.cmp.com','876543','4'" 
>>> words = added.split(',') 
>>> words 
["'hypr1005.ops.colo.cmp.com'", "'web1234.ads.colo.cmp.com'", "'876543'", "'4'"] 
>>>