rank（）函数SQL

Question

我想排列以下得分表，其中相同的得分将具有相同的等级。

+----+-------+ 
| Id | Score | 
+----+-------+ 
| 1 | 3.50 | 
| 2 | 4.00 | 
| 3 | 4.00 | 
| 4 | 3.50 | 
+----+-------+ 

有人可以帮助为什么是以下查询抛出语法错误？另外，逻辑不正确？

代码：

select Score, RANK() OVER (order by Score desc) as rank 
from Scores 
order by Score desc; 

错误消息：

Line 1: SyntaxError: near '(order by Score desc) as rank 
from Scores 
order by Score desc' 

Answer 1

如：（假设你想和1居第2，而不是1和3）

SELECT x.* 
    , CASE WHEN @prev = score THEN @i:=@i ELSE @i:=@i+1 END rank 
    , @prev:=score 
    FROM my_table x 
    , (SELECT @prev:=null,@i:=0) vars 
ORDER 
    BY score DESC 
    , id; 

对于体育排名，你可以这样做：

SELECT a.* 
    , FIND_IN_SET(score, 
        (SELECT GROUP_CONCAT(score ORDER BY score DESC) 
         -- inclusion of DISTINCT here will output as above 
         FROM my_table) 
        ) x 
    FROM my_table a; 

但也有与此解决方案