在Base64 ActionScript 3.0中解码XML

Question

我试图导入已在Flash中进行Base64编码的XML文件。进口是相当简单的：

var myXML:XML; 
var myLoader:URLLoader = new URLLoader(); 
myLoader.load(new URLRequest("encoded.xml")); 
myLoader.addEventListener(Event.COMPLETE, processXML); 

function processXML(e:Event):void 
{ 
    myXML = new XML(e.target.data); 
    trace(myXML); 
} 

现在我想知道如何解码它。我找到了一个我认为可以工作的类，但是我不确定如何在导入后将其应用于XML。我的问题是，我将如何使用下面的类来解码XML，或者我有另一种方法来解决这个问题吗？

package com.base64 { 
    /** 
    * Encodes and decodes a base64 string. 
    * @authors Sven Dens - http://www.svendens.be 
    * @version 0.1 
    * 
    * Original Javascript implementation: 
    * Aardwulf Systems, www.aardwulf.com 
    * See: http://www.aardwulf.com/tutor/base64/base64.html 
    */ 
    import flash.system.System; 

    public class Base64 { 
     /** 
     * Variables 
     * @exclude 
     */ 
     protected static var base64chars:String = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz/="; 

     /** 
     * Encodes a base64 string. 
     */ 
     public static function encode(src:String):String { 
      var i:Number = 0; 
      var output:String = new String(""); 
      var chr1:Number, chr2:Number, chr3:Number; 
      var enc1:Number, enc2:Number, enc3:Number, enc4:Number; 
      while (i < src.length) { 
       chr1 = src.charCodeAt(i++); 
       chr2 = src.charCodeAt(i++); 
       chr3 = src.charCodeAt(i++); 
       enc1 = chr1 >> 2; 
       enc2 = ((chr1 & 3) << 4) | (chr2 >> 4); 
       enc3 = ((chr2 & 15) << 2) | (chr3 >> 6); 
       enc4 = chr3 & 63; 
       if(isNaN(chr2)) enc3 = enc4 = 64; 
       else if(isNaN(chr3)) enc4 = 64; 
       output += base64chars.charAt(enc1)+base64chars.charAt(enc2); 
       output += base64chars.charAt(enc3)+base64chars.charAt(enc4) 
      } 
      return output; 
     } 

     /** 
     * Decodes a base64 string. 
     */ 
     public static function decode(src:String):String { 
      var i:Number = 0; 
      var output:String = new String(""); 
      var chr1:Number, chr2:Number, chr3:Number; 
      var enc1:Number, enc2:Number, enc3:Number, enc4:Number; 
      while (i < src.length) { 
       enc1 = base64chars.indexOf(src.charAt(i++)); 
       enc2 = base64chars.indexOf(src.charAt(i++)); 
       enc3 = base64chars.indexOf(src.charAt(i++)); 
       enc4 = base64chars.indexOf(src.charAt(i++)); 
       chr1 = (enc1 << 2) | (enc2 >> 4); 
       chr2 = ((enc2 & 15) << 4) | (enc3 >> 2); 
       chr3 = ((enc3 & 3) << 6) | enc4; 
       output += String.fromCharCode(chr1); 
       if (enc3 != 64) output = output+String.fromCharCode(chr2); 
       if (enc4 != 64) output = output+String.fromCharCode(chr3); 
      } 
      return output; 
     } 

    } 
} 

Answer 1

好，使用你的类，它应该是这么简单

myXML = XML(Base64.decode(e.target.data)); 

如果它不工作，检查解码器的返回值：

trace(Base64.decode(e.target.data));