1
目标:如果我输入一个电子邮件ID,在html表单中它必须发送请求到jsp,在那里它执行逻辑并且必须打印(在html表单中)电子邮件是否可用,或者不。我有以下代码。请帮助我,我做错了哪一部分。JSP + Ajax无法正常工作
CreateAccount.html
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<script type="text/javascript" src="emailStore.js"></script>
</head>
<body onload="process()">
<form name="login">
<table align="center">
<tr>
<td>Email*</td>
<td><input type="text" name="userinput" id="userinput"/></td>
<td><div id = "underInput"></div></td>
</tr>
<tr>
<td>Password*</td>
<td><input type="password" name="pswrd" /></td>
</tr>
<tr>
<td>Repeat Password*</td>
<td><input type="password" name="pswrd1" /></td>
</tr>
<tr>
<td>First Name*</td>
<td><input type="text" name="userid" /></td>
</tr>
<tr>
<td>Last Name*</td>
<td><input type="text" name="userid" /></td>
</tr>
<tr>
<td>Phone Number</td>
<td><input type="text" name="userid" /></td>
</tr>
</table>
<div style="text-align: center">
<input type="submit" value="Create Account"/>
</div>
</form>
</body>
</html>
JavaScript文件中的AJAX部分。 emailStore.js
var xmlHttp = createXmlHttpRequestObject();
function createXmlHttpRequest()
{
var xmlHttp;
if(window.ActiveXObject)
{
try
{
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
catch(e)
{
xmlHttp = false;
}
}
else
{
try
{
xmlHttp = new ActiveXObject();
}
catch(e)
{
xmlHttp = false;
}
}
if(!xmlHttp)
{
alert("can't create that object");
}
else
{
return xmlHttp;
}
}
function process()
{
if(xmlHttp.readyState==0 || xmlHttp.readyState==4)
{
email = encodeURIComponent(document.getElementById("userinput").value);
xmlHttp.open("GET", "emailStore.jsp?email=" + email, true);
xml.onreadystatechange = handle.ServerResponse;
xmlHttp.send(null);
}
else
{
setTimeout('process()', 1000);
}
}
function handleServerResponse()
{
if(xmlHttp.readyState==4)
{
if(xmlHttp.status==200)
{
xmlResponse = xmlHttp.responseXML;
xmlDocumentElement = xmlResponse.documentElement;
message = xmlDocumentElement.firstChild.data;
document.getElementById("underInput").innerHTML = '<span style = "color:blue">' + message + '</span>';
setTimeout('process()',1000);
}
else
{
alert('Something went Wrong');
}
}
}
并在JSP逻辑部分文件 - emailStore.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@ page import="java.util.ArrayList"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<%
String email = request.getParameter("userinput");
ArrayList<String> emails = new ArrayList<String>();
emails.add("[email protected]");
if (emails.contains(email)) {
out.println("Email already taken!");
} else {
out.println("Email available");
}
%>
</body>
</html>
什么是不工作是什么意思?请分享任何异常,这是一个冗长的代码。 – NINCOMPOOP
不会抛出任何异常。但它不能正常工作。 – Arun
如果你在响应中不需要HTML,你不应该首先使用JSP。请不要在JSP中编写Java代码,请使用Servlet。 – NINCOMPOOP