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我在社交网站上工作。在第一次加载时,它会提取所有帖子,每个帖子都有两个注释最大值。如果评论超过两个 它附加More comment
按钮,如果点击,它会显示所有评论,并用Less comment
替换按钮。AJAX内的AJAX无法正常工作
这只是它的一个小故事。我希望每当发表评论时,它都应附加到现有的评论中,并通过 AJAX即时显示。为此,它会,但它重新显示每个注释3次,当你重新加载页面,一切都还好...
<div class = 'post_updates'>
<div class = 'feeds'>
<div class = 'commentdiv'>
<textarea autocomplete = 'off' class='commenttext form-control' rows = '1'
placeholder='Have your say...'></textarea>
<button class='comment btn btn-xs btn-primary onespacedown' value = '7'
type='submit'>Comment</button>
</div>
</div>
</div>
jQuery的AJAX代码:
$('.feeds').on('click', '.comment', function() {
var $this = $(this);
var post_comment = $this.parents('.feeds').find('.commenttext').val();
var post_id = $(this).val();
var user_id = $(".user_id").text();
var request = $.ajax({
url: "insert.php",
type: "POST",
data: { post : post_id , user : user_id, comment: post_comment },
dataType: "html"
});
request.done(function(msg) {
$pc = $this.parents('.feeds').find('.per_comment');
//fetch comments and display
var request = $.ajax({
url: "comments.php",
type: "POST",
data: {
post: post_id,
user: user_id
},
dataType: "html"
});
request.done(function (msg) {
$pc.html(msg).data('loaded', true);
$this.replaceWith("<button class='lesscomments btn-block pullcomments' value='' name = 'more' type='submit'>Less comments</button>");
$this.parents('.feeds').find('.commenttext').val('');
});
});
})
在前进,谢谢。 jQuery中
@Tats_innit:jQuery.ajax处理继续回应:“成功:” VS“.done”(http://stackoverflow.com/q/8840257/1438393) –
@Tats_innit'success'与'done'完全相同... – Yax
Agreed @AmalMurali我错过了第二个电话:http://stackoverflow.com/questions/8847829/what-is-difference-between-success - 完成方法的AJAX –