// Get the #1 app name from iTunes and SwiftyJSON
DataManager.getTopAppsDataFromItunesWithSuccess { (iTunesData) -> Void in
let json = JSON(data: iTunesData)
println(json)
如何访问[“场地”] [“酒吧城”] [“场地”]的所有元素?迅速 - 如何解析这个JSON对象
{
"venues":{
"cityuser":"Beirut",
"venue-usernewplace":{
"star":[
],
"idcat":[
],
"namecat":[
],
"name":[
],
"id":[
],
"phone":[
],
"address":[
],
"crossStreet":[
],
"lat":[
],
"lng":[
],
"cc":[
]
},
"placesofpeople":{
"star":"false",
"nameplace":"B0 18",
"idplace":"4b52670df964a520847b27e3",
"count":"4",
"cc":"LB",
"phone":"01580018",
"crossStreet":"Main Highway",
"lat":"33.898404713314",
"lng":"35.534128372291",
"address":"Karantina"
},
"pubcity":{
"venue":[
{
"id":"4fe75b17e4b032d653ce50fd",
"idcat":"4bf58dd8d48988d11e941735",
"name":"Cl\u00e9 Cafe-Lounge Bar",
"phone":"71200712",
"address":"Mohammed Abdel Baki Street, Clemenceau",
"crossStreet":"Hamra, Facing Najjar Hospital",
"lat":"33.897185328966",
"lng":"35.487202808518",
"cc":"LB",
"count":"0",
"namecat":"Cocktail Bar",
"star":"false"
},
{
"id":"4e3e7533fa76455375c56a33",
"idcat":"4bf58dd8d48988d11f941735",
"name":"Skybar",
"phone":"03939191",
"address":"Biel",
"crossStreet":"Downtown Beirut",
"lat":"33.90610643966",
"lng":"35.510663636771",
"cc":"LB",
"count":"0",
"namecat":"Nightclub",
"star":"false"
},
{
"id":"4b52670df964a520847b27e3",
"idcat":"4bf58dd8d48988d11f941735",
"name":"B 018",
"phone":"01580018",
"address":"Karantina",
"crossStreet":"Main Highway",
"lat":"33.898404713314",
"lng":"35.534128372291",
"cc":"LB",
"count":"0",
"namecat":"Nightclub",
"star":"false"
},
把printn当(JSON)一切都出现! – 2015-02-08 00:49:50
转到json.org并了解JSON语法。学习只需要5-10分钟。然后明白,当解析JSON时,JSON“对象”翻译成NSDictionary,JSON“数组”翻译成NSArray。编写代码来访问每个连续的图层,有效地像洋葱一样“剥离”JSON。 **不要求有人给你写代码!! ** – 2015-02-08 02:42:37
而''“场地”] [“酒吧城”] [“场地”]'是一个数组。你知道如何处理数组吗? – 2015-02-08 02:45:31