刚刚写了一个模板数组类的代码(我知道它还没有完成),并试图记住如何重载运算符(同时没有特别的困难...)。重载运算符[]为模板类C++
无论如何,当考虑如何实现operator[]
我想知道如果索引超出数组边界会发生什么......我敢肯定,我不可能返回一个NULL(因为返回类型),对吗?如果是的话,如果指数超出边界,我应该返回什么?
这里的代码,其中大部分是多余的,我的问题,但它可能会帮助任何人谁谷歌的运营商超载,所以我张贴的完整代码...
#ifndef __MYARRAY_H
#define __MYARRAY_H
#include <iostream>
using namespace std;
template <class T>
class MyArray
{
int phisicalSize, logicalSize;
char printDelimiter;
T* arr;
public:
MyArray(int size=10, char printDelimiter=' ');
MyArray(const MyArray& other);
~MyArray() {delete []arr;}
const MyArray& operator=(const MyArray& other);
const MyArray& operator+=(const T& newVal);
T& operator[](int index);
friend ostream& operator<<(ostream& os, const MyArray& ma)
{
for(int i=0; i<ma.logicalSize; i++)
os << ma.arr[i] << ma.printDelimiter;
return os;
}
};
template <class T>
T& MyArray<T>::operator[](int index)
{
if (index < 0 || index > logicalSize)
{
//do what???
}
return arr[index];
}
template <class T>
const MyArray<T>& MyArray<T>::operator+=(const T& newVal)
{
if (logicalSize < phisicalSize)
{
arr[logicalSize] = newVal;
logicalSize++;
}
return *this;
}
template <class T>
const MyArray<T>& MyArray<T>::operator=(const MyArray<T>& other)
{
if (this != &other)
{
delete []arr;
phisicalSize = other.phisicalSize;
logicalSize = other.logicalSize;
printDelimiter = other.printDelimiter;
arr = new T[phisicalSize];
for(int i=0; i<logicalSize; i++)
arr[i] = other.arr[i];
}
return *this;
}
template <class T>
MyArray<T>::MyArray(const MyArray& other) : arr(NULL)
{
*this = other;
}
template <class T>
MyArray<T>::MyArray(int size, char printDelimiter) : phisicalSize(size), logicalSize(0), printDelimiter(printDelimiter)
{
arr = new T[phisicalSize];
}
#endif
你应该-at most _assert_,它是一个错误,以索引一个数组超越其边界... –
'__MYARRAY_H'是一个[保留](http://stackoverflow.com/questions/228783/what-are-关于使用下划线的ac标识符)标识符。 – chris
你可能会抛出异常。 – brain