boost :: python转换std :: array

Question

我正在使用std :: array来为最短路径函数定义2D点。

typedef std::array<double, 2> point_xy_t; 
typedef std::vector<point_xy_t> path_t; 
path_t search(const point_xy_t& start, const point_xy_t& goal); 

现在，我最好的解决办法是点转换（STD ::数组）到std ::向量，并使用boost ::蟒蛇:: vector_indexing_suite为：

bpy::class_<std::vector<double> >("Point") 
    .def(bpy::vector_indexing_suite<std::vector<double> >()) 
; 
bpy::class_<std::vector<std::vector<double>> >("Path") 
    .def(bpy::vector_indexing_suite<std::vector<std::vector<double>> >()) 
; 

它会可以索引或直接从/到std ::数组转换为/从python？

Answer 1

为了给它pythonic外观，我会使用boost::python::extract,tuple和list的组合。这里是一个草图：

static bpy::list py_search(bpy::tuple start, bpy::tuple goal) { 
    // optionally check that start and goal have the required 
    // size of 2 using bpy::len() 

    // convert arguments and call the C++ search method 
    std::array<double,2> _start = {bpy::extract<double>(start[0]), bpy::extract<double>(start[1])}; 
    std::array<double,2> _goal = {bpy::extract<double>(goal[0]), bpy::extract<double>(goal[1])}; 
    std::vector<std::array<double,2>> cxx_retval = search(_start, _goal); 

    // converts the returned value into a list of 2-tuples 
    bpy::list retval; 
    for (auto &i : cxx_retval) retval.append(bpy::make_tuple(i[0], i[1])); 
    return retval; 
} 

然后绑定应该是这样的：

bpy::def("search", &py_search);