我想用外键request.user
创建一个SpiderService
。django-rest-framework反序列化请求创建一个用户外键的对象
型号:
from django.contrib.auth.models import User
class SpiderService(models.Model):
user = models.ForeignKey(User)
name = models.CharField(max_length=20)
串行:
class SpiderServiceSerializer(serializers.ModelSerializer):
user = serializers.ReadOnlyField(source='user.id')
class Meta:
model = SpiderService
fields = ('id', 'user', 'name')
class SpiderServiceListSerializer(viewsets.ModelViewSet):
queryset = SpiderService.objects.all()
serializer_class = SpiderService
观点:
class SpiderServiceList(APIView):
def get(self, request, format=None):
services = SpiderService.objects.all()
serializer = SpiderServiceSerializer(services, many=True)
return Response(serializer.data)
def post(self, request, format=None):
serializer = SpiderServiceSerializer(data=request.data)
if serializer.is_valid():
serializer.save()
return Response(serializer.data, status=status.HTTP_201_CREATED)
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
def perform_create(elf, serializer):
serializer.save(user=self.request.user)
发帖时
{
"name": "2"
}
的API URL,得到500错误:
[01/Feb/2016 15:39:55] "POST /services/ HTTP/1.1" 500 17105
IntegrityError: NOT NULL constraint failed: spmanage_spiderservice.user_id
我已阅读Serializer relations,发现我不应该写代码如上。官方示例等于在SpiderServiceSerializer
中删除user field
,并将spiderservice field
添加到UserSerializer
。示例旨在在django模型中实现类似user.spiderservice_set
的语法,这不符合我的目的。
我只想创建一个带有request.user
的spiderservice对象。
如何解决?
你是对的,谢谢!但有没有另一种方式来自动填充用户字段?在删除user = serializers.ReadOnlyField(source ='user.id')'后,它说''user''是必需的。 – Mithril
我没有得到你的评论 – Linovia
你说我的用户字段是'read_only',所以我删除它。然后发生验证错误,说“用户”是必需的。这是否意味着我必须自己保存一个外键? – Mithril