的MySQL：查询用于过滤列后获得最大价值

Question

我有以下表

+------------+-------+------------+-----------+ 
| date  | time | custom_id | Number | 
+------------+-------+------------+-----------+ 
| 01/02/2014 | 01:00 | ABC123  | 15  | 
| 01/06/2014 | 02:00 | ABC123  | 11  | 
| 01/06/2014 | 00:00 | ABC123  | 17  | 
| 01/06/2014 | 01:00 | HEY567  | 28  | 
| 01/07/2014 | 01:00 | ABC123  | 17  | 
| 01/08/2014 | 00:00 | HEY567  | 28  | 
| 01/09/2014 | 14:00 | ABC123  | 17  | 
| 01/10/2014 | 22:00 | HEY567  | 28  | 
| 01/10/2014 | 23:00 | ABC123  | 17  | 
| 01/12/2014 | 18:30 | HEY567  | 28  | 
+------------+-------+------------+-----------+ 

如何我：

1. 选择从2014年1月6日日期范围从时间开始00:00 UNTIL 01/10/2014 at 23:00

2. 顺序MAX到MIN列名为每天

3. 排序也基于该custom_id表列数

我会喜欢它最终看起来类似于：

+------------+-------+------------+-----------+ 
| date  | time | custom_id | Number | 
+------------+-------+------------+-----------+ 
| 01/06/2014 | 01:00 | HEY567  | 28  | 
| 01/06/2014 | 00:00 | ABC123  | 17  | 
| 01/06/2014 | 02:00 | ABC123  | 11  | 
| 01/07/2014 | 01:00 | ABC123  | 17  | 
| 01/08/2014 | 00:00 | HEY567  | 28  | 
| 01/09/2014 | 14:00 | ABC123  | 17  | 
| 01/10/2014 | 22:00 | HEY567  | 28  | 
| 01/10/2014 | 23:00 | ABC123  | 17  | 
+------------+-------+------------+-----------+ 

我该如何用MySQL Query来完成这项工作？

在此先感谢

SQLFiddle与查询我没有更早：http://sqlfiddle.com/#!2/3d2b9/1

Answer 1

我真的该custom_id不知道，如果你的列“时间”的数据，如'23：30' ，这可能工作：

SELECT date, time, custom_id, Number 
FROM traffic 
WHERE CONCAT(date, " ", time) BETWEEN "01/06/2014 00:00" AND "01/10/2014 23:00" 
ORDER BY date, CAST(Number as SIGNED) DESC, custom_id 

按照CONCAT合并“日期”和“时间”。

http://sqlfiddle.com/#!2/f57b7/8

Answer 2

这里是一个MySQL查询，将查找日期2014年1月6日和2014年1月10日再下订单之间由按降序排列数列，按升序

SELECT date, MIN(time) as time, custom_id, SUM(Number) as numbersum 
FROM traffic 
WHERE time between "00:00" and "23:00" and date between "01/06/2014" and "01/10/2014" 
GROUP BY date, custom_id, HOUR(time) 
ORDER BY numbersum desc, custom_id