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我想要做一个数据的非规范化以提高性能,并把我的博客文章接收Post模型内的票数总和访问原始(未修改)实例:Django的:如何在post_save信号
class Post(models.Model):
""" Blog entry """
author = models.ForeignKey(User)
title = models.CharField(max_length=255)
text = models.TextField()
rating = models.IntegerField(default=0) # here is the sum of votes!
class Vote(models.Model):
""" Vote for blog entry """
post = models.ForeignKey(Post)
voter = models.ForeignKey(User)
value = models.IntegerField()
Ofcourse,我需要保持Post.rating
的实际值。 Nornally我会用数据库触发器对于这一点,但现在我已经决定做一个post_save
信号(减少数据库的处理时间):
# vote was saved
@receiver(post_save, sender=Vote)
def update_post_votes(sender, instance, created, **kwargs):
""" Update post rating """
if created:
instance.post.rating += instance.value
instance.post.save()
else:
# if vote was updated, we need to remove the old vote value and add the new one
# but how...?
我如何可访问对象的值保存它之前?在数据库触发器中,我会为此预定义OLD
和NEW
,但在post_save信号中是否有这样的内容?
UPDATE
根据马克的答案解决办法:
# vote was saved
@receiver(pre_save, sender=Vote)
def update_post_votes_on_save(sender, instance, **kwargs):
""" Update post rating """
# if vote is being updated, then we must remove previous value first
if instance.id:
old_vote = Vote.objects.get(pk=instance.id)
instance.post.rating -= old_vote.value
# now adding the new vote
instance.post.rating += instance.value
instance.post.save()
谢谢,你是绝对正确的。结果是,当instans被创建时,它在pre_save信号中没有'id',但是如果它正在更新,它有一个'id'。这正是我所需要的,请参阅实际解决方案的问题更新。 – 2011-04-08 11:24:09