获取URL的动态内容？

Question

我使用MWFeedParser来返回来自BBC新闻RSS源的故事。他们返回下面，作为一个例子：

item: MWFeedItem: “Woman guilty of family fire killings” - 2013-04-30 15:04:31 +0000 
identifier: http://www.bbc.co.uk/news/uk-wales-22294592 
title: Woman guilty of family fire killings 
link: http://www.bbc.co.uk/news/uk-wales-22294592#sa-ns_mchannel=rss&ns_source=PublicRSS20-sa 
date: 2013-04-30 15:04:31 +0000 
updated: (null) 
summary: A woman is convicted of murdering five members of a neighbouring family, including three children, by starting a house fire. 
content: (null) 
enclosures: (null) 

去其中的任一环节的返回物品，像这样： http://www.bbc.co.uk/news/uk-wales-22294592

我想从该页面的图像和文章内容。我该怎么做呢？

Answer 1

您已经采取了第一步：您知道该文章在http://www.bbc.co.uk/news/uk-wales-22294592。所以你从那个页面下载内容并解析它。