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我想在Scala中递归解压缩文件我已经修改了现有的Java代码到scala语法。斯卡拉字节数组类型不匹配错误
在我的代码中的一个点,我声明一个字节数组来读取数据,我得到以下错误:类型不匹配;发现:数组[java.lang.Byte中]要求:数组[scala.Byte]
而且我inputstream.read功能给我的一个错误:替代品读重载的方法值:(X $ 1:数组[斯卡拉Int()int(x $ 1:Array [scala.Byte])Int不能应用于(Array [java.lang.Byte],Int,Int)
我想这也是由于该数组的声明。我该如何解决这个问题?有没有办法将java.lang.Byte转换为scala.Byte?
这是我的代码:
import java.io._;
import org.apache.log4j._
import org.apache.spark.SparkContext
import java.io.IOException
import scala.collection.JavaConversions._
import java.io.FileInputStream
import java.io.FileOutputStream
import java.util.zip.ZipEntry
import java.util.zip.ZipInputStream
import java.util.zip.ZipEntry
import java.util.zip.ZipFile
import java.io.InputStream
import java.io.OutputStream
import java.io.File
import java.lang.Byte
object MultiLevelUnzip
{
val BUFFER = 2048
def main (args:Array[String])
{
Logger.getLogger("org").setLevel(Level.ERROR)
val sc = new SparkContext("local[*]","Unzip")
//val Files = sc.listFiles()
sc.stop()
}
def findFiles(d : File): Array[File] =
{
val (dirs, files) = d.listFiles.partition(_.isDirectory)
files ++ dirs.flatMap(findFiles)
}
def extractFolder(zipFile:String)=
{
System.out.println(zipFile);
val file = new File(zipFile);
val zip = new ZipFile(file);
val newPath = zipFile.substring(0, zipFile.length() - 4);
new File(newPath).mkdir();
var zipFileEntries = zip.entries()
// Process each entry
while (zipFileEntries.hasMoreElements())
{
// grab a zip file entry
val entry = zipFileEntries.nextElement()
val currentEntry = entry.getName()
val destFile = new File(newPath, currentEntry);
//destFile = new File(newPath, destFile.getName());
val destinationParent = destFile.getParentFile();
// create the parent directory structure if needed
destinationParent.mkdirs();
if (!entry.isDirectory())
{
val is = new BufferedInputStream(zip.getInputStream(entry))
var currentByte = null
// establish buffer for writing file
// val buffer = Array.fill[Byte](BUFFER)(_)
// write the current file to disk
val fos = new FileOutputStream(destFile)
val dest = new BufferedOutputStream(fos,BUFFER)
val data = new Array[Byte](BUFFER)
while ((currentByte = is.read(data,0, BUFFER)) != -1) {
dest.write(data, 0, currentByte);
}
dest.flush();
dest.close();
is.close();
}
if (currentEntry.endsWith(".zip"))
{
// found a zip file, try to open
extractFolder(destFile.getAbsolutePath());
}
}
}
}
之大,工作,但在使用编译型scala.Byte ((currentByte = is.read(data,0,BUFFER))!= -1) { dest.write(data,0,currentByte); } 我仍然在类型不匹配的读取函数中出现错误,其中预计发现null并且发现Int。 关于如何解决这个问题的任何想法? –