斯卡拉酱菜类型不匹配

Question

我用scala的pickle序列化玩了一下，所以我编写了一个Netty Handler，但是当我尝试使用scalac编译文件时，由于类型不匹配而导致错误，我无法解释我

import java.util 

import io.netty.buffer.ByteBuf 
import io.netty.channel.ChannelHandlerContext 
import io.netty.handler.codec.{MessageToMessageDecoder, MessageToMessageEncoder} 

import scala.pickling._ 

import scala.pickling.binary._ 

import scala.pickling.json._ 






class PickleEncoder(format: PickleFormat = scala.pickling.binary.pickleFormat) extends MessageToMessageEncoder[AnyRef] { 

    implicit val pickleFormat = format 

    override def encode(implicit ctx: ChannelHandlerContext, msg: AnyRef, out: util.List[AnyRef]): Unit = { 
    val pickled: Pickle = msg.pickle 
    val bytes = pickled.value match { 
     case bytes: Array[Byte] => bytes 
     case json: String => json.getBytes("UTF-8") 
     case _ => throw PicklingException("Unable to detect pickle format") 
    } 
    out.add(bytes.toByteBuf) 
    } 


} 

class PickleDecoder(format: PickleFormat = scala.pickling.binary.pickleFormat) extends MessageToMessageDecoder[ByteBuf] { 

    implicit val pickleFormat = format 

    override def decode(ctx: ChannelHandlerContext, msg: ByteBuf, out: util.List[AnyRef]) = { 
    val bytes: Array[Byte] = msg.toBytes 
    val data = format match { 
     case scala.pickling.binary.pickleFormat => bytes.unpickle[AnyRef] 
     case scala.pickling.json.pickleFormat => new String(bytes, "UTF-8").unpickle[AnyRef] 
     case _ => throw PicklingException("Unable to detect pickle format") 
    } 
    out.add(data) 
    } 
} 

编译错误：

Error:(30, 31) type mismatch; found : scala.pickling.Pickle 
required: PickleEncoder.this.pickleFormat.PickleType 
    val pickled: Pickle = msg.pickle 

任何想法的问题是什么？ ^

Answer 1

问题是scala和scala-pickle之间的二进制不匹配，它编译了正确的版本。