1
我有一个表order_details
这样嵌套查询返回值
id | SKU | quantity_purchased | discount_price
---------------------------------------------------
1 | abc | 1 | 10.0
2 | abc | 90 | 00
2 | abc | 9 | 00
3 | xyz | 1 | 50.0
3 | xyz | 2 | 50.0
4 | xyz | 100 | 00
4 | xyz | 100 | 00
-----------------------------------------------
我的查询是
select
(select sum(quantity_purchased) from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased) from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
GROUP BY sku
我需要的结果是
SKU | quantity_original | quantity_discount
---------------------------------------------------
abc | 1 | 99
xyz | 3 | 200
-----------------------------------------------
也就是说,我需要两列计算后相同sku
,
我无法建立的逻辑,我在嵌套查询使用GROUP BY
试过,但它不工作... 任何帮助,高度赞赏.. 感谢
UPDATE: 尝试通过做这不过还是失败,
select
(select sum(quantity_purchased) from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased) from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
where sku = (select distinct sku from order_details)
GROUP BY sku
+1,真棒....太感谢了,你让我很快乐的老板......一两件事,好像你已经互换列名(原已经成为折扣)但这不是问题,有你的逻辑,谢谢十亿...你真的帮了很多... –
啊...你已经纠正它,再次感谢... –