2017-01-17 90 views
0

我有两个输入CSV文件,一个为会员和一个用于他们看起来像下面 enter image description here的BizTalk XSLT映射

会员XML看起来像

<Root xmlns="http://TestTwoInput.MemberSchema"> 
    <Record xmlns=""> 
    <EmployeeID>12</EmployeeID> 
    <MemberText>MEMBER</MemberText> 
    <SPID>007609952</SPID> 
    <MPID>007609952</MPID> 
    <SAID>12</SAID> 
    <ACode>05</ACode> 
    </Record> 
    <Record xmlns=""> 
    <EmployeeID>14</EmployeeID> 
    <MemberText>MEMBER</MemberText> 
    <SPID>004482352</SPID> 
    <MPID>004482352</MPID> 
    <SAID>14</SAID> 
    <ACode>05</ACode> 
    </Record> 
    </Root> 

效益XML看起来像

<Root xmlns="http://TestTwoInput.BenefitSchema"> 
<Record xmlns=""> 
    <EmployeeID>12</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>MEA</BCode> 
    <ELR>001</ELR> 
    <Control>0100189</Control> 
    </Record> 
<Record xmlns=""> 
    <EmployeeID>12</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>DEN</BCode> 
    <ELR>002</ELR> 
    <Control>0100189</Control> 
    </Record> 
<Record xmlns=""> 
    <EmployeeID>14</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>DEN</BCode> 
    <ELR>002</ELR> 
    <Control>0100189</Control> 
    </Record> 
<Record xmlns=""> 
    <EmployeeID>14</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>MEA</BCode> 
    <ELR>001</ELR> 
    <Control>0100189</Control> 
    </Record> 
<Record xmlns=""> 
    <EmployeeID>14</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>MEA</BCode> 
    <ELR>001</ELR> 
    <Control>0100189</Control> 
    </Record> 
<Record xmlns=""> 
    <EmployeeID>14</EmployeeID> 
    <BenefitText>BENEFIT</BenefitText> 
    <BCode>DEN</BCode> 
    <ELR>002</ELR> 
    <Control>0100189</Control> 
    </Record> 
    </Root> 
效益

这两个输入都有EmployeeID字段。我需要与他们的利益

12,MEMBER,007609952,007609952,12,05 
12,BENEFIT,MEA,001,0100189 
12,BENEFIT,DEN,002,0100189 
14,MEMBER,004482352,004482352,14,05 
14,BENEFIT,DEN,002,0100189 
14,BENEFIT,MEA,001,0100189 
14,BENEFIT,MEA,001,0100189 
14,BENEFIT,DEN,002,0100189 

这是我的地图 enter image description here 映射两个文件能像每个成员一个输出但是,这将引发类似

12,MEMBER,007609952,007609952,12,05 
12,BENEFIT,MEA,001,0100189 
12,BENEFIT,DEN,002,0100189 
,,,, 
,,,, 
,,,, 
,,,, 
14,MEMBER,004482352,004482352,14,05 
12,BENEFIT,MEA,001,0100189 
12,BENEFIT,DEN,002,0100189 
,,,, 
,,,, 
,,,, 
,,,, 

下面XSLT输出映射

<?xml version="1.0" encoding="UTF-16"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s1 s0 s2 userCSharp" version="1.0" xmlns:s1="http://TestTwoInput.BenefitSchema" xmlns:ns0="http://TestTwoInput.OutputSchema" xmlns:s0="http://TestTwoInput.MemberSchema" xmlns:s2="http://schemas.microsoft.com/BizTalk/2003/aggschema" xmlns:userCSharp="http://schemas.microsoft.com/BizTalk/2003/userCSharp"> 
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" /> 
<xsl:template match="/"> 
<xsl:apply-templates select="/s2:Root" /> 
</xsl:template> 
<xsl:template match="/s2:Root"> 
<ns0:Root> 
    <xsl:for-each select="InputMessagePart_0/s0:Root/Record"> 
    <Record> 
     <Member> 
     <EID> 
      <xsl:value-of select="EmployeeID/text()" /> 
     </EID> 
     <Text> 
      <xsl:value-of select="MemberText/text()" /> 
     </Text> 
     <SPID> 
      <xsl:value-of select="SPID/text()" /> 
     </SPID> 
     <MPID> 
      <xsl:value-of select="MPID/text()" /> 
     </MPID> 
     <SIAD> 
      <xsl:value-of select="SAID/text()" /> 
     </SIAD> 
     <ACode> 
      <xsl:value-of select="ACode/text()" /> 
     </ACode> 
     </Member> 
     <xsl:for-each select="../../../InputMessagePart_1/s1:Root/Record"> 
     <xsl:variable name="var:v1" select="userCSharp:LogicalEq(string(EmployeeID/text()) , string(../../../InputMessagePart_0/s0:Root/Record/EmployeeID/text()))" /> 
     <xsl:variable name="var:v3" select="string(EmployeeID/text())" /> 
     <xsl:variable name="var:v4" select="string(../../../InputMessagePart_0/s0:Root/Record/EmployeeID/text())" /> 
     <xsl:variable name="var:v5" select="userCSharp:LogicalEq($var:v3 , $var:v4)" /> 
     <Benefit> 
      <xsl:if test="string($var:v1)='true'"> 
      <xsl:variable name="var:v2" select="EmployeeID/text()" /> 
      <ID> 
       <xsl:value-of select="$var:v2" /> 
      </ID> 
      </xsl:if> 
      <xsl:if test="string($var:v5)='true'"> 
      <xsl:variable name="var:v6" select="BenefitText/text()" /> 
      <Text> 
       <xsl:value-of select="$var:v6" /> 
      </Text> 
      </xsl:if> 
      <xsl:if test="string($var:v5)='true'"> 
      <xsl:variable name="var:v7" select="BCode/text()" /> 
      <BCode> 
       <xsl:value-of select="$var:v7" /> 
      </BCode> 
      </xsl:if> 
      <xsl:if test="string($var:v5)='true'"> 
      <xsl:variable name="var:v8" select="ELR/text()" /> 
      <ELR> 
       <xsl:value-of select="$var:v8" /> 
      </ELR> 
      </xsl:if> 
      <xsl:if test="string($var:v5)='true'"> 
      <xsl:variable name="var:v9" select="Control/text()" /> 
      <Control> 
       <xsl:value-of select="$var:v9" /> 
      </Control> 
      </xsl:if> 
     </Benefit> 
     </xsl:for-each> 
    </Record> 
    </xsl:for-each> 
    </ns0:Root> 
</xsl:template> 
<msxsl:script language="C#" implements-prefix="userCSharp"><![CDATA[ 
public bool LogicalEq(string val1, string val2) 
{ 
bool ret = false; 
double d1 = 0; 
double d2 = 0; 
if (IsNumeric(val1, ref d1) && IsNumeric(val2, ref d2)) 
{ 
    ret = d1 == d2; 
} 
else 
{ 
    ret = String.Compare(val1, val2, StringComparison.Ordinal) == 0; 
} 
return ret; 
} 

public bool IsNumeric(string val) 
{ 
if (val == null) 
{ 
    return false; 
} 
double d = 0; 
return Double.TryParse(val, System.Globalization.NumberStyles.AllowThousands | System.Globalization.NumberStyles.Float, System.Globalization.CultureInfo.InvariantCulture, out d); 
} 

public bool IsNumeric(string val, ref double d) 
{ 
if (val == null) 
{ 
    return false; 
} 
return Double.TryParse(val, System.Globalization.NumberStyles.AllowThousands | System.Globalization.NumberStyles.Float, System.Globalization.CultureInfo.InvariantCulture, out d); 
} 


]]></msxsl:script> 
</xsl:stylesheet> 

我不知道如何通过XSLT实现输出。任何帮助,这是不胜感激

+1

您似乎已经多次发布这个问题,略有不同的措辞。如果您希望将其作为XSLT问题提供帮助,请将您的源代码__XML__(例如,通过BizTalk运行的本机平面文件)和预期的输出__XML__与您尝试的XSLT一起包含在内(这里似乎包含此处以及其他一些帖子) 。如果他们不具有建设性,请回去并删除类似的问题。 –

+0

@DanField我在这里发布一个之前删除了我之前的问题。我已经使用输入XML编辑了我的问题。请帮我做这个 – trx

回答

1

好的。所以张贴您的输入消息是不是很是什么样子的aggschema格式,这将是这样的:

<Root xmlns="http://schemas.microsoft.com/BizTalk/2003/aggschema"> 
    <InputMessagePart_0 xmlns=""> 
    <Root xmlns="http://TestTwoInput.MemberSchema"> 
     <Record xmlns=""> 
     <EmployeeID>12</EmployeeID> 
     <MemberText>MEMBER</MemberText> 
     <SPID>007609952</SPID> 
     <MPID>007609952</MPID> 
     <SAID>12</SAID> 
     <ACode>05</ACode> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>14</EmployeeID> 
     <MemberText>MEMBER</MemberText> 
     <SPID>004482352</SPID> 
     <MPID>004482352</MPID> 
     <SAID>14</SAID> 
     <ACode>05</ACode> 
     </Record> 
    </Root> 
    </InputMessagePart_0> 
    <InputMessagePart_1 xmlns=""> 
    <Root xmlns="http://TestTwoInput.BenefitSchema"> 
     <Record xmlns=""> 
     <EmployeeID>12</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>12</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>14</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>14</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>14</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Record> 
     <Record xmlns=""> 
     <EmployeeID>14</EmployeeID> 
     <BenefitText>BENEFIT</BenefitText> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Record> 
    </Root> 
    </InputMessagePart_1> 
</Root> 

这种情况并没有真正严格要求Muenchian分组的,它只是需要一点更多地控制BizTalk不允许通过标准映射设计器的for-each(BizTalk中的循环函数)。如果你看看输出XSLT,你会注意到它在嵌套for-each循环的方式以及它如何试图测试EmployeeID节点之间的相等性方面做了一些非感性的事情。以下是定制的XSLT应该如何看,正确的嵌套(和删除的BizTalk的产生和不必要的变量):

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s1 s0 s2 userCSharp" version="1.0" xmlns:s1="http://TestTwoInput.BenefitSchema" xmlns:ns0="http://TestTwoInput.OutputSchema" xmlns:s0="http://TestTwoInput.MemberSchema" xmlns:s2="http://schemas.microsoft.com/BizTalk/2003/aggschema" xmlns:userCSharp="http://schemas.microsoft.com/BizTalk/2003/userCSharp"> 
    <xsl:output omit-xml-declaration="yes" indent="yes" method="xml" version="1.0" /> 
    <xsl:template match="/"> 
    <xsl:apply-templates select="/s2:Root" /> 
    </xsl:template> 
    <xsl:template match="/s2:Root"> 
    <ns0:Root> 
     <xsl:for-each select="InputMessagePart_0/s0:Root/Record">   
     <Record> 
      <Member> 
      <EID> 
       <xsl:value-of select="EmployeeID/text()" /> 
      </EID> 
      <Text> 
       <xsl:value-of select="MemberText/text()" /> 
      </Text> 
      <SPID> 
       <xsl:value-of select="SPID/text()" /> 
      </SPID> 
      <MPID> 
       <xsl:value-of select="MPID/text()" /> 
      </MPID> 
      <SIAD> 
       <xsl:value-of select="SAID/text()" /> 
      </SIAD> 
      <ACode> 
       <xsl:value-of select="ACode/text()" /> 
      </ACode> 
      </Member> 
      <xsl:variable name="empID" select="EmployeeID" /> 
      <xsl:for-each select="../../../InputMessagePart_1/s1:Root/Record[EmployeeID = $empID]"> 
      <Benefit>    
       <ID> 
       <xsl:value-of select="EmployeeID/text()" /> 
       </ID> 
       <Text> 
       <xsl:value-of select="BenefitText/text()" /> 
       </Text> 
       <BCode> 
       <xsl:value-of select="BCode/text()" /> 
       </BCode> 
       <ELR> 
       <xsl:value-of select="ELR/text()" /> 
       </ELR> 
       <Control> 
       <xsl:value-of select="Control/text()" /> 
       </Control> 
      </Benefit> 
      </xsl:for-each> 
     </Record> 
     </xsl:for-each> 
    </ns0:Root> 
    </xsl:template> 
</xsl:stylesheet> 

这给你以下的输出:

<ns0:Root xmlns:ns0="http://TestTwoInput.OutputSchema"> 
    <Record> 
     <Member> 
     <EID>12</EID> 
     <Text>MEMBER</Text> 
     <SPID>007609952</SPID> 
     <MPID>007609952</MPID> 
     <SIAD>12</SIAD> 
     <ACode>05</ACode> 
     </Member> 
     <Benefit> 
     <ID>12</ID> 
     <Text>BENEFIT</Text> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
     <Benefit> 
     <ID>12</ID> 
     <Text>BENEFIT</Text> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
    </Record> 
    <Record> 
     <Member> 
     <EID>14</EID> 
     <Text>MEMBER</Text> 
     <SPID>004482352</SPID> 
     <MPID>004482352</MPID> 
     <SIAD>14</SIAD> 
     <ACode>05</ACode> 
     </Member> 
     <Benefit> 
     <ID>14</ID> 
     <Text>BENEFIT</Text> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
     <Benefit> 
     <ID>14</ID> 
     <Text>BENEFIT</Text> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
     <Benefit> 
     <ID>14</ID> 
     <Text>BENEFIT</Text> 
     <BCode>MEA</BCode> 
     <ELR>001</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
     <Benefit> 
     <ID>14</ID> 
     <Text>BENEFIT</Text> 
     <BCode>DEN</BCode> 
     <ELR>002</ELR> 
     <Control>0100189</Control> 
     </Benefit> 
    </Record> 
</ns0:Root> 

这里是上面的一个XslTransform一起玩:http://xsltransform.net/3NSSEvs

您可能会通过使用xsl:key(Muenchian分组)来获得更好的性能 - 如果您打算在较大的文档结果集上​​使用此功能,请进行一些研究;但是如果你的文件看起来像你通常在这里发送的,你应该没问题。说实话,如果它们变得非常大,我会建议在源代码处重构一些东西,而不是试图用XSLT来解决所有问题 - 如果可能的话,限制生成平面文件的任何过程(也许在SQL中做了更多的工作SQL实际上通过它合并一些数据和/或页面),或者在C#中编写自定义组件来处理它们比XSLT引擎最终能够更有效地合并它们。

+0

谢谢丹。我对XSLT映射很陌生。从我当前的映射中,我应该删除输入和输出模式之间的所有链接,并使用XSLT代码。正如您所说,源代码是Oracle数据库的视图,并且成员记录有近2000条记录,优点是12000条记录。 – trx

+0

如果使用自定义c#组件。可以在映射中使用它吗? – trx

+0

我会避免完全为该卷的地图。 XSLT不会很好地扩展,地图将使用大量的内存。你应该寻找更好的方法来在SQL中准备你的数据,或者使用诸如'XmlReader'之类的流式管道组件来处理它。 –