的Biztalk：映射

Question

中分组项有没有办法采取看起来像这样的XML文件：

<?xml version="1.0" encoding="utf-8"?> 
<spMyStoredProc xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo"> 
<StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>1</Item> 
     <Property>something</property> 
    </StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>2</Item> 
     <Property>something</property> 
    </StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>3</Item> 
     <Property>something</property> 
     <Group>1</Group> 
    </StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>4</Item> 
     <Property>something</property> 
     <Group>1</Group> 
    </StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>5</Item> 
     <Property>something</property> 
     <Group>2</Group> 
    </StoredProcedureResultSet0> 
    <StoredProcedureResultSet0 xmlns="http://schemas.microsoft.com/Sql/2008/05/TypedProcedures/dbo/spMyStoredProc"> 
     <Item>6</Item> 
     <Property>something</property> 
     <Group>2</Group> 
    </StoredProcedureResultSet0> 
    </StoredProcedureResultSet0> 
    <ReturnValue>0</ReturnValue> 
</spMyStoredProc> 

出来的格式如下：

<MyRequests> 
    <Request> 
     <Item ID="1" Property="Something" /> 
    </Request> 
    <Request> 
     <Item ID="2" Property="Something" /> 
    </Request> 
    <Request GroupID="1"> 
     <Item ID="3" Property="Something" /> 
     <Item ID="4" Property="Something" /> 
    </Request> 
    <Request GroupID="2"> 
     <Item ID="5" Property="Something" /> 
     <Item ID="6" Property="Something" /> 
    </Request> 
</MyRequests> 

我亲近只是用从源模式到目的地的直接映射，但它不会将具有相同组ID的项组合在一起。

基本上，我能够得到没有functoid的是这样的：

<MyRequests> 
    <Request> 
     <Item ID="1" Property="Something" /> 
    </Request> 
    <Request> 
     <Item ID="2" Property="Something" /> 
    </Request> 
    <Request GroupID="1"> 
     <Item ID="3" Property="Something" /> 
    </Request> 
    <Request GroupID="1"> 
     <Item ID="4" Property="Something" /> 
    </Request> 
    <Request GroupID="2"> 
     <Item ID="5" Property="Something" /> 
    </Request> 
    <Request GroupID="2"> 
     <Item ID="6" Property="Something" /> 
    </Request> 
</MyRequests> 

Answer 1

这听起来像XSLT 2.0 isn't supported in Biztalk，所以这个答案是关于XSLT 1.0。

假设你的XML输入文件是良好的，即包装在单个顶层元素...

对于这种分组问题的标准方法是Meunchian分组。例如参见https://stackoverflow.com/a/1929273/423105或https://stackoverflow.com/a/2334224/423105。如果您在应用这些答案时遇到困难，请留下具体问题的评论。