Richtextbox上的编号列表

Question

我试图将编号列表功能添加到文本编辑器。 RichTextbox已经提供SelectionBullet属性来将选项更改为项目符号列表。但我无法找到类似的属性来生成编号列表。是否有任何标准方式在Richtextbox上创建编号列表。 如果不是，我将不得不自己实现，所以代码剪辑可以帮助我做，这将有助于，谢谢。

Answer 1

我知道一个链接并没有被普遍接受为一个好的答案，但是CodeProject上的文章RichTextBox with Search Line Numbering, Bulleting, Printing, Searching Support可能会帮助你找到你想要的东西。

在本文中，作者将RichTextBox控件扩展为可以做你正在问的事情（以及更多），再加上代码发布给所有人看。

Answer 2

那么，我执行它如下。

private void btnNumbers_Click(object sender, EventArgs e) 
     { 
      string temptext = rtbMain.SelectedText; 

      int SelectionStart = rtbMain.SelectionStart; 
      int SelectionLength = rtbMain.SelectionLength; 

      rtbMain.SelectionStart = rtbMain.GetFirstCharIndexOfCurrentLine(); 
      rtbMain.SelectionLength = 0; 
      rtbMain.SelectedText = "1. "; 

      int j = 2; 
      for(int i = SelectionStart; i < SelectionStart + SelectionLength; i++) 
       if (rtbMain.Text[i] == '\n') 
       { 
        rtbMain.SelectionStart = i + 1; 
        rtbMain.SelectionLength = 0; 
        rtbMain.SelectedText = j.ToString() + ". "; 
        j++; 
        SelectionLength += 3; 
       } 

     } 

     private void rtbMain_KeyDown(object sender, KeyEventArgs e) 
     {//this piece of code automatically increments the bulleted list when user //presses Enter key 
      int tempNum; 
      if (e.KeyCode == Keys.Enter) 
       try 
        { 
         if (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine()])) 
         { 
          if (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1]) && rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 2] == '.') 
           tempNum = int.Parse(rtbMain.Text.Substring(rtbMain.GetFirstCharIndexOfCurrentLine(),2)); 
          else tempNum = int.Parse(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine()].ToString()); 

          if (rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1] == '.' || (char.IsDigit(rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 1]) && rtbMain.Text[rtbMain.GetFirstCharIndexOfCurrentLine() + 2] == '.')) 
          { 
           tempNum++; 
            rtbMain.SelectedText = "\r\n" + tempNum.ToString() + ". "; 
           e.SuppressKeyPress = true; 
          } 
         } 
        } 
       catch{} 
     } 

Answer 3

这是我的答案...它易于阅读和优化。我采取了一种非常不同的方法，但添加了删除选择内的编号列表（如果它已存在）的功能。请注意，到目前为止，我只是轻微地测试它，它似乎运作良好......但它可能需要进一步改进。

private void btnOrdered_Click(object sender, EventArgs e) 
    { 
     string[] splitSelection = null; 
     // If selection split selection else split everything 
     if (this.txtCaptionEditor.SelectionLength > 0) 
     { 
      splitSelection = this.txtCaptionEditor.SelectedText.Replace("\r\n", "\n").Split("\n".ToCharArray()); 
     } 
     else 
     { 
      splitSelection = this.txtCaptionEditor.Text.Replace("\r\n", "\n").Split("\n".ToCharArray()); 
     } 
     bool Exists = false; 
     for (int i = 0; i < splitSelection.GetLength(0); i++) 
     { 
      // If Ordered List Allready exists in selection then remove else add 
      if (!string.IsNullOrEmpty(splitSelection[i])) 
      { 
       if (splitSelection[i].Substring(0, 2) == "1.") { Exists = true; } 
      } 
     } 

     for (int i = 0; i < splitSelection.GetLength(0); i++) 
     { 
      int lineCount = (i + 1); 
      if (Exists) 
      { 
       this.txtCaptionEditor.Text = this.txtCaptionEditor.Text.Replace(Convert.ToString(lineCount) + ". ", ""); 
      } 
      else 
      { 
       if(!string.IsNullOrEmpty(splitSelection[i])) 
       { 
        this.txtCaptionEditor.Text = this.txtCaptionEditor.Text.Replace(splitSelection[i], Convert.ToString(lineCount) + ". " + splitSelection[i]); 
       } 

      } 
     } 
    } 

    private void txtCaptionEditor_KeyDown(object sender, KeyEventArgs e) 
    { 
     string[] splitSelection = this.txtCaptionEditor.Text.Replace("\r\n", "\n").Split("\n".ToCharArray()); 
     if (e.KeyCode == Keys.Enter) 
     { 
      // Get Current Line Position 
      int currentLine = this.txtCaptionEditor.GetLineFromCharIndex(this.txtCaptionEditor.SelectionStart); 
      // Only Run if the previous line is greater than zero 
      if ((currentLine) >= 0) 
      { 
       // Loop through 100 possible numbers for match you can go higher 
       // If you think your numbered list could go above 100 
       for (int i = 0; i < 100; i++) 
       { 
        if (splitSelection[(currentLine)].Substring(0, 2) == Convert.ToString((i + 1)) + ".") 
        { 
         // If the substring of the current line equals a numbered list    value.. enumerate next line 
         this.txtCaptionEditor.SelectedText = "\n" + (i + 2) + ". "; 
         e.SuppressKeyPress = true; 
        } 
       } 
      } 
     } 
    }