泛型 - 迭代ArrayList时的ClassCastException

Question

以下是我的代码。我正在查询user_group表并将结果显示在列表中。我想迭代列表。但得到例外如下。

List<Group> list= empDAO.getStudentList(); 
    for(Group o :list){ 
     System.out.println("NAME :"+ o.getFirstName()); 
    } 

这是我的DAO方法

public List<Group> getStudentList() { 
    System.out.println("INSIDE DAO"); 
    List<Group> groups = new ArrayList<Group>(); 

    List<Group> rows = jdbcTemplate.queryForList("select * from user_group"); 

    return rows; 
} 

Group.class

public class Group { 
    public Group() { 
     // TODO Auto-generated constructor stub 
    } 

    private String firstName; 

    public String getFirstName() { 
     return firstName; 
    } 

    public void setFirstName(String firstName) { 
     this.firstName = firstName; 
    } 
} 

我收到以下异常

Aug 3, 2012 9:22:47 PM org.apache.catalina.core.StandardWrapperValve invoke 
SEVERE: Servlet.service() for servlet mvc-dispatcher threw exception 
java.lang.ClassCastException: java.util.LinkedHashMap cannot be cast to com.common.form.Group 
     at com.common.controller.HelloWorldController.helloWorld(HelloWorldController.java:28) 
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
     at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
     at java.lang.reflect.Method.invoke(Method.java:597) 
     at org.springframework.web.bind.annotation.support.HandlerMethodInvoker.doInvokeMethod(HandlerMethodInvoker.java:421) 
     at org.springframework.web.bind.annotation.support.HandlerMethodInvoker.invokeHandlerMethod(HandlerMethodInvoker.java:136) 
     at org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.invokeHandlerMethod(AnnotationMethodHandlerAdapter.java:326) 
     at org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.handle(AnnotationMethodHandlerAdapter.java:313) 
     at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875) 
     at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:807) 
     at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571) 
     at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:617) 
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) 
     at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) 
     at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) 
     at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) 
     at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) 
     at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) 
     at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) 
     at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) 
     at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) 
     at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857) 
     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) 
     at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) 
     at java.lang.Thread.run(Thread.java:619) 

谁能告诉如何解决这一问题错误？

Answer 1

行jdbcTemplate.queryForList("select * from user_group");正在返回一个HashMap列表，而不是一个组列表项（您的IDE可能在该行上显示警告）。

您可能想阅读关于jdbcTemplate的Spring文档，并且您可能希望使用RowMapper将每行都转换为Group对象。

我也认为你想用你的用例的方法jdbcTemplate.query(String sql, RowMapper rm)，检查javadoc。

Answer 2

jdbcTemplate.queryForList不返回List<Group>，它不知道Group是什么。它返回一个List<Map<String,Object>>（行列表），每一行都是从列名称到其值的映射。

所以做到这一点：

for (Map<String,Object> m : jdbcTemplate.queryForList("select * from user_group")) { 
    for (Map.Entry<String,Object> e : m.entrySet()) { 
     String columnName = e.key; 
     Object columnValue = e.value; 
     ...build a Group somehow?... 
    } 
}