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def interval(a,b,n):
dx = float(b-a)/(n+1)
cnt = 1
points = [a]
xj = a
while cnt <= n+1:
xj += dx
points.append(xj)
cnt+=1
return points
def interval(a,b,n):
dx = float(b-a)/(n+1)
cnt = 1
points = [a]
xj = a
while cnt <= n+1:
xj += dx
points.append(xj)
cnt+=1
return points
更换你的函数如下给出: -
def interval(a,b,n):
dx = float(b-a)/(n+1)
points = [a]
xj = a
points.extend([xj + (i * dx) for i in xrange(1, n+2)])
return points
为什么你需要它作为一个列表理解? – wwii
,因为列表理解比循环操作简单和短。 – user59220
是什么问题?请尝试。 – wwii