MS Access Switch综合功能

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我有以下SQL语句。但是，它无法运行。它说的是：MS Access Switch综合功能

你的查询不包括指定表达式 “则DateValue（开关（小时（[日期时间]）> = 18和小时（[日期时间]）< 22，[日期时间] （[日期时间]）> = 22，[日期时间]，小时（[日期时间]）> = 0和小时（[日期时间]）< 2，[日期时间] ）> = 2和小时（[日期时间]）< 6，[日期时间] -1，小时（[日期时间]）> = 6和小时（[日期时间]）< 10，[日期时间] - 1，Hour（[Date Time]）> = 10 And Hour（[Date Time]）< 14，[Date Time] -1，Hour（[Date Time]）> = 14 And Hour（[Date Time]） < 18，[Date Time] -1））作为DateValue'作为聚合函数的一部分。

SELECT DateValue(Switch(Hour([Date Time])>=18 And Hour([Date Time])<22,[Date Time],Hour([Date Time])>=22,[Date Time],Hour([Date Time])>=0 And Hour([Date Time])<2,[Date Time],Hour([Date Time])>=2 And Hour([Date Time])<6,[Date Time]-1,Hour([Date Time])>=6 And Hour([Date Time])<10,[Date Time]-1,Hour([Date Time])>=10 And Hour([Date Time])<14,[Date Time]-1,Hour([Date Time])>=14 And Hour([Date Time])<18,[Date Time]-1)) As DateValue, Avg([MFR g/10min]) AS Average, Max([MFR g/10min]) - Min([MFR g/10min]) As Difference 
FROM [In process analysis result] 
GROUP BY DateValue([Date Time]);

是否有任何线索有什么不好？

编辑1：如果我运行下面的查询，它会工作：

SELECT DateValue(Switch(Hour([Date Time])>=18 And Hour([Date Time])<22,[Date Time],Hour([Date Time])>=22,[Date Time],Hour([Date Time])>=0 And Hour([Date Time])<2,[Date Time],Hour([Date Time])>=2 And Hour([Date Time])<6,[Date Time]-1,Hour([Date Time])>=6 And Hour([Date Time])<10,[Date Time]-1,Hour([Date Time])>=10 And Hour([Date Time])<14,[Date Time]-1,Hour([Date Time])>=14 And Hour([Date Time])<18,[Date Time]-1)) AS DateValue, Avg([MFR g/10min]) AS Average, Max([MFR g/10min]) - Min([MFR g/10min]) As Difference FROM [In process analysis result] GROUP BY Switch(Hour([Date Time])>=18 And Hour([Date Time])<22,[Date Time],Hour([Date Time])>=22,[Date Time],Hour([Date Time])>=0 And Hour([Date Time])<2,[Date Time],Hour([Date Time])>=2 And Hour([Date Time])<6,[Date Time]-1,Hour([Date Time])>=6 And Hour([Date Time])<10,[Date Time]-1,Hour([Date Time])>=10 And Hour([Date Time])<14,[Date Time]-1,Hour([Date Time])>=14 And Hour([Date Time])<18,[Date Time]-1);

然而，结果不是我所期待的。我试图通过组列之日起，DateValue：

的则DateValue（）没有被分组，我不能让马克斯和Min之间的平均和差异性。

请帮助...

来源

2017-01-11 Yong Xiang Soh

可能的复制 - SQL查询每天数据的平均值]（http://stackoverflow.com/questions/41581378/ms-access-sql-query-for-average-of-each-day-data） – Gustav

你不会抵消DateTime这种价值。研究你的其他问题。 – Gustav

您的分组功能应该是一样的选择（补充：则DateValue（）到您的分组标准）：[MS访问的

SELECT DateValue(Switch(Hour([Date Time])>=18 And Hour([Date Time])<22,[Date Time],Hour([Date Time])>=22,[Date Time],Hour([Date Time])>=0 And Hour([Date Time])<2,[Date Time],Hour([Date Time])>=2 And Hour([Date Time])<6,[Date Time]-1,Hour([Date Time])>=6 And Hour([Date Time])<10,[Date Time]-1,Hour([Date Time])>=10 And Hour([Date Time])<14,[Date Time]-1,Hour([Date Time])>=14 And Hour([Date Time])<18,[Date Time]-1)) AS DateValue, Avg([MFR g/10min]) AS Average, Max([MFR g/10min]) - Min([MFR g/10min]) As Difference FROM [In process analysis result] GROUP BY DateValue(Switch(Hour([Date Time])>=18 And Hour([Date Time])<22,[Date Time],Hour([Date Time])>=22,[Date Time],Hour([Date Time])>=0 And Hour([Date Time])<2,[Date Time],Hour([Date Time])>=2 And Hour([Date Time])<6,[Date Time]-1,Hour([Date Time])>=6 And Hour([Date Time])<10,[Date Time]-1,Hour([Date Time])>=10 And Hour([Date Time])<14,[Date Time]-1,Hour([Date Time])>=14 And Hour([Date Time])<18,[Date Time]-1));

来源

2017-01-11 10:07:16 snibbo

MS Access Switch综合功能

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