2016-11-21 64 views
5

我有一个小菜单,我想通过数据库表中的id类似下面的命令:顺序菜单节点

public class Obj 
    { 
     public string Value { get; set; } 
     public int? ParentNodeId { get; set; } 
     public int? PreviousNodeId { get; set; } 
     public int? NextNodeId { get; set; } 
    } 

private IEnumerable<MenuNodeDTO> GetSortedMenuNodes(int menuId) 
    { 
     var nodes = LoadMenuNodes(menuId); 
     foreach (MenuNode menuNode in nodes 
      .Where(s => s.MenuItemId == null && s.ParentNodeId == null) 
      .OrderBy(x => x?.PreviousNodeId) 
      .Where(x => x.PreviousNodeId != x.Id)) 
     { 
      MenuNodeDTO tmpMenuNode = new MenuNodeDTO(); 
      tmpMenuNode.MenuNodeDtoId = menuNode.Id; 
      tmpMenuNode.MenuItemCode = menuNode.MenuItem?.Code; 
      tmpMenuNode.ChildMenuNodes = GetChildNodes(menuNode).ToList(); 
      tmpMenuNode.MenuSettings = GetMenuSettings(menuNode).ToList(); 
      yield return tmpMenuNode; 
     } 
} 

例子:

Id = 1 MainMenuPoint1 ParentNodeId = null, PreviousNodeId = null, NextNodeId = 4 
Id = 2 -> 1 ChildNodeFromPoint1 ParentNodeId = 1, PreviousNodeId = null, NextNodeId = null 
Id = 3 --> ChildNodeFromFirstChildNode1 ParentNodeId = 2, PreviousNodeId = null, NextNodeId = null 
Id = 4 MainMenuPoint2 ParentNodeId = null, PreviousNodeId = 1, NextNodeId = null 

与我的每个问题是,当id改变了排序不起作用。 有人知道如何通过parentid,previousid和next id命令来检查每次所有关系的ID吗?

+1

至于我,我会建议另一个数据库结构:'ParentNodeId'和'Order'。你可以使用DFS来订购你的节点,并且可以使用Order来订购叶子。顺序也不能保证是明显的,节点1的所有子项都可以有顺序= 0 - 这意味着它们应该按名称\ ID \排序,无论如何,这并不重要。 –

+1

@YeldarKurmangaliyev问题在于当你改变菜单结构,移动节点或删除节点时,你会怎么做? –

+1

谈论顺序,移除或移动一个节点什么也不会改变 - 它工作得很好。谈到父母关系,如果它有子节点,你就无法删除一个节点。这是数据完整性的问题。在删除它之前,您需要清除其子节点列表。 –

回答

1
private IEnumerable<MenuNodeDTO> GetSortedNodes(Menu menu, MenuNode node) 
     { 
      List<MenuNodeDTO> items = new List<MenuNodeDTO>(); 

      var nodes = node != null ? node.ChildMenuNodes : menu.MenuNodes; 
      var nextNode = node == null 
       ? nodes.Where(c => c.PreviousNodeId == null && c.ParentNodeId == null).FirstOrDefault() 
       : nodes.Where(c => c.ParentNodeId == node.Id && c.PreviousNodeId == null).FirstOrDefault(); 

      while (nextNode != null) 
      { 
       MenuNodeDTO tmpMenuNode = new MenuNodeDTO(); 
       tmpMenuNode.MenuNodeDtoId = nextNode.Id; 
       tmpMenuNode.MenuItemCode = nextNode?.MenuItem?.Code; 
       tmpMenuNode.ChildMenuNodes = this.GetSortedNodes(menu, nextNode).ToList(); 
       tmpMenuNode.MenuSettings = GetMenuSettings(nextNode).ToList(); 
       items.Add(tmpMenuNode); 
       if (!nextNode.NextNodeId.HasValue) break; 
       nextNode = nextNode.NextNode; 
      } 
      return items; 
     }