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我有一个注册页面jQuery的弹出用PHP表单验证
<form class="register" action="regist.php" method="post" >
<h3>Register</h3>
<div class="column">
<div>
<label>First Name:</label>
<input type="text" name="f_name"/>
<span ></span>
</div>
<div>
<label>Last Name:</label>
<input type="text" name="l_name"/>
<span class="error">This is an error</span>
</div>
<div>
<label>mobile:</label>
<input type="text" name="mobile"/>
<span class="error">This is an error</span>
</div>
</div>
<div class="column">
<div>
<label>Username:</label>
<input type="text"name="user"/>
<span >This is an error</span>
</div>
<div>
<label>Email:</label>
<input type="text" name="email"/>
<span class="error">This is an error</span>
</div>
<div>
<label>Password:</label>
<input type="password" name="pass"/>
<span class="error">This is an error</span>
</div>
</div>
<div class="bottom">
<div class="remember">
</div>
<input type="submit" value="Register" name="submet" />
<a href="index.html" rel="login" class="linkform">You have an account already? Log in here</a>
<div class="clear"></div>
</div>
</form>
使用jQuery的bpopup
$(function() {
// Binding a click event
// From jQuery v.1.7.0 use .on() instead of .bind()
$('#my-button').bind('click', function(e) {
// Prevents the default action to be triggered.
e.preventDefault();
// Triggering bPopup when click event is fired
$('#element_to_pop_up').bPopup();
});
}
所以当有人点击注册表单将罚款弹出的每一件事情的工作问题是,我不能验证的形式,因为当我点击注册后填写表格 弹出将消失,所以我不能做验证在同一表格
我试图 1使另一个弹出显示错误,但数据不会传递到新弹出 2做出行动$_SERVER['self_request']
有人可以帮助我这个请我有我的大学项目我需要做它在3个dayes
我需要的是在同一个页面或之前另一个弹出窗体验证其发送到MySQL脚本