之间插入三角洲个XML向表SQL

Question

我有2个XML赞（标签是动态的）：

Declare @OldXml xml = <Data><testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId><description>Test1</description><Name>aaaa</Name><createdBy>1111</createdBy><updatedBy>1111</updatedBy></Data> 

Declare @NewXml xml = '<Data><testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId><description>Test2</description><Name>bbbb</Name><createdBy>1111</createdBy><updatedBy>2222</updatedBy></Data>' 

我要进入它们之间的区别到另一个表像：

entity          Field    OldValue  NewValue 
    ----------------------------------------------------------------------------------------- 
    BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2  description   Test1   Test2 
    BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2   Name    aaaa   bbbb 

我该怎么做？

嗨，经过长时间的搜寻后，我找到了答案

SELECT DISTINCT 
    foo.bar.value('local-name(.)','VARCHAR(14)') as FieldName, 
    foo.bar.value('./.','VARCHAR(14)') as OldValue , 
    foo1.bar1.value('./.','VARCHAR(14)') as NewValue , 
    FROM 
    @OldXml.nodes('/Data/*') AS foo(bar) 
    INNER JOIN @NewXml.nodes('/Data/*') AS foo1(bar1) ON foo.bar.value('local-name(.)','VARCHAR(14)') = foo1.bar1.value('local-name(.)','VARCHAR(14)') 
                             AND foo.bar.value('./.','VARCHAR(14)') <> foo1.bar1.value('./.','VARCHAR(14)') 

实体，我会分别得到。
谢谢大家

Answer 1

SQL Fiddle

declare @OldXml xml = ' 
<Data> 
    <testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId> 
    <description>Test1</description> 
    <Name>aaaa</Name> 
    <createdBy>1111</createdBy> 
    <updatedBy>1111</updatedBy> 
</Data> 
' 
declare @NewXml XML = ' 
<Data> 
    <testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId> 
    <description>Test2</description> 
    <Name>bbbb</Name> 
    <createdBy>1111</createdBy> 
    <updatedBy>2222</updatedBy> 
</Data>' 

select @OldXml.value('(Data/testId/text())[1]', 'uniqueidentifier') as entity, 
     T.Field, 
     @OldXml.value('(/Data/*[local-name(.) = sql:column("T.Field")]/text())[1]', 'nvarchar(max)') as OldValue, 
     @NewXml.value('(/Data/*[local-name(.) = sql:column("T.Field")]/text())[1]', 'nvarchar(max)') as NewValue 
from (
    select T.X.value('local-name(.)', 'nvarchar(max)') as Field 
    from @OldXml.nodes('/Data/*') as T(X) 
    ) as T 

Results：

|        ENTITY |  FIELD |        OLDVALUE |        NEWVALUE | 
------------------------------------------------------------------------------------------------------------------------------------ 
| BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 |  testId | BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 | BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 | 
| BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 | description |        Test1 |        Test2 | 
| BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 |  Name |         aaaa |         bbbb | 
| BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 | createdBy |         1111 |         1111 | 
| BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2 | updatedBy |         1111 |         2222 | 

Answer 2

尝试这一个 -

DECLARE 
     @OldXml XML = '<Data><testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId><description>Test1</description><Name>aaaa</Name><createdBy>1111</createdBy><updatedBy>1111</updatedBy></Data>' 
    , @NewXml XML = '<Data><testId>BE7F2CDE-0D31-4E47-AA07-CE179F1E47C2</testId><description>Test2</description><Name>bbbb</Name><createdBy>1111</createdBy><updatedBy>2222</updatedBy></Data>' 

SELECT id = 'NEW' 
     , testId = t.c.value('(./testId)[1]', 'UNIQUEIDENTIFIER') 
     , [description] = t.c.value('(./description)[1]', 'NVARCHAR(100)') 
     , createdBy = t.c.value('(./createdBy)[1]', 'INT') 
     , updatedBy = t.c.value('(./updatedBy)[1]', 'INT') 
FROM @NewXml.nodes('/Data') t(c) 

UNION ALL 

SELECT id = 'OLD' 
    , t.c.value('(./testId)[1]', 'UNIQUEIDENTIFIER') 
    , t.c.value('(./description)[1]', 'NVARCHAR(100)') 
    , t.c.value('(./createdBy)[1]', 'INT') 
    , t.c.value('(./updatedBy)[1]', 'INT') 
FROM @OldXml.nodes('/Data') t(c)