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#include <string.h>
#include <stdio.h>
#include <ctype.h>
#define SIZE 100
const char delim[] = ", . - !*()&^%$#@<> ? []{}";
int main(void)
{
int length[SIZE] = { 0 };
int name[SIZE];
int i = 0, ch;
int wordlength = 0;
int occurence = 0;
printf("Please enter sentence, end the setence with proper punctuation(! . ?) : ");
while (1)
{
ch = getchar();
if (isalpha(ch))
{
++wordlength;
}
else if (strchr(delim, ch))
{
if (wordlength)
{
length[wordlength - 1]++;
}
if(ch == '.' || ch == '?' || ch == '!')
{
break;
}
if(ch == '\'')
{
wordlength++;
}
wordlength = 0;
}
}
printf("Word Length \tOccurence \n");
for(i = 0; i<sizeof(length)/sizeof(*length); ++i)
{
if(length[i])
{
printf(" %d \t\t%d\n", i + 1, length[i]);
}
}
return 0;
}
所以程序应该算冒了一句,如...字长度计不计算单引号为字符
"Hello how are you?"
然后输出:
5 Letter Words -> 1
3 Letter Words -> 3
不过我希望它也可以将单引号计为一个字符,例如...
输入:
输出:
4 Letter words -> 2
我已经尝试使用...
if(ch == '\'')
{
wordlength++;
}
但它只是不计数单引号的字符。
为什么你需要逃脱单引号? –